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telo118 [61]
3 years ago
7

A 300 kg dragster accelerates from the rest to the final speed of 120 m/s in 400 m (about a quarter of a mile) and encounters an

average frictional force of 1200 N. What is the average output in watts AND horsepower if this takes 7.30 seconds?
Business
1 answer:
Naddik [55]3 years ago
7 0
Let P<span> be the average power output. The total amount of work done is </span><span><span>P*(7.3s)</span>)</span><span>. But the total amount of work done is also the sum of these two quantities:
1._ </span>The work done to overcome friction. 2._The kinetic energy of the dragster at the end of the 400 m. Then the first part of the work done is (1200N)*(400m)=480000 J.  
 Part 2 is given by the kinetic energy formula: 1/2*(300)*(120^2)=2160000 J.
<span>Taken together, that's 2640000 J.
</span>Divide by the time <span>(7.3s)</span><span> and you have average power output of about
</span><span> 361643.836 Watts and in HP is </span> 361643.836/745.7=<span><span>484.972289 HP</span></span>
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