Due to the high crash rates among young drivers, Driver's education or communication campaigns are being implemented in some states to reduce the rate or to solve the critical issue. Special courses for young drivers<span> to make them conscious about their personal tendencies that may affect their behavior towards driving can be helpful.</span>
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Answer:
Competition decreases your market share and shrinks your customer base, especially if demand for your products or services is limited from the start. A competitive market can also force you to lower your prices to stay competitive, decreasing your return on each item you produce and sell.
You would have to invest 97,222
97222*6=5833.32 + 97222= 103055.32 Year one
103055.32*.06= 6183.32 = 109238.64 Year two
109238.64*.06= 6554.32= 115792.96 Year three
115792.96*.06= 6947.58 = 122740.54 Year four
Answer:
The answer is a. True.
Explanation:
During the initial stages, the members might be concerned that the project work might be difficult and this can act as a demotivating factor in the long run.
Because of this, if the manager can start the initial stages of planning of the operating methods, thus will be helpful to ease the tension and the doubts among the members.
Answer:
Part a: The probability of breaking even in 6 tosses is 0.3125.
Part b: The probability that one payer wins all the money after the 10th toss is 0.0264.
Explanation:
Part a
P(success)=1/2=0.5
P(Failure)=1/2=0.5
Now for the break-even at the sixth toss
P(Break Even)=P(3 success out of 6)
P(3 success out of 6)

So the probability of breaking even in 6 tosses is 0.3125.
Part b:
So the probability that one of the player wins all the money after the 10th toss is given as the tenth toss is given as a win so
Wins in 9 tosses is given as 9!/7!=72
The probability that the other person wins
Wins in 8 out of 10 tosses is given as 10!/8!(10-8)!=10!/8!2!=45
So the probability of all the money is won by one of the gambler after the 10th toss is given as
P=number of wins in 9 tosses-Number of wins in 10 tosses/total number of tosses
P=(72-45)/2^16
P=0.0264
So the probability that one payer wins all the money after the 10th toss is 0.0264.