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Alexus [3.1K]
4 years ago
8

What is 3940 times 4869

Mathematics
2 answers:
Ratling [72]4 years ago
6 0
The answer is simply 19,183,860
r-ruslan [8.4K]4 years ago
4 0

Answer:


Step-by-step explanation:

4869 x 3940 = 19183860

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How many different 4-digit numbers can be formed using only digits 1, 2, 3, and 4, given that they contain each of these digits
emmainna [20.7K]
24 4 digit numbers can be formed using 1234
8 0
4 years ago
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ANSWER PLS URGENT VERY URGENT TYSM ik its a lot of questions but id really really be grateful for the help
anyanavicka [17]

Step-by-step explanation:

about circle R

arc angle MP = angle MRP = 78°

angle M = angle LMP.

according to the rules of inscribed angles, LMP is half of angle LRP.

LRP + MRP = 180° because together they cover the whole LM segment (half-circle).

LRP = 180 - MRP = 180 - 78 = 102°

so, LMP = angle M = 102/2 = 61°

also circle R (with arc ULNP)

the arc ULNP = arc UL + arc LN + arc NP = 160°

due to the congruent definition of JU and MP we know that arc UL = arc NP.

and we know arc LN = arc JM = 18°.

so,

160 = 2×arc NP + 18

142 = 2×arc NP

arc NP = 71° = arc UL

now, because arc MP + arc LP = 180 (half-circle),

arc MP = 180 - arc LP = 180 - arc LN - arc NP =

= 180 - 18 - 71 = 91°

about the circle R with 2 congruent chords :

the second answer : they are equidistant from R (the center of the circle).

about circle W

arc MK + arc KL = 180° (half-circle).

and we see

arc HL = arc KL = 53°.

so,

arc MK + 53 = 180°

arc MK = 180 - 53 = 127°

about circle M

arc QTS = 204°.

therefore, arc QRS = 360 - arc QTS = 360 - 204 =

= 156° = angle QMS.

according to the rules of inscribed angles

angle QTS = QMS/2 = 156/2 = 78°

4 0
2 years ago
20 fish are in a bowl 8 die three swim away and six drown how many arein the bowl?
BaLLatris [955]
20-8=12
12-3=9
9-6=3
3 fish are in a bowl.
Have a fab sunday!
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3 years ago
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An ellipse has vertices at (0, #17) and foci at (0, ±15). Write the equation of the ellipse in standard form. Graph the ellipse.
Lunna [17]

<u>ANSWER</u>

\frac{ {x}^{2} }{ 64 }  +  \frac{ {y}^{2} }{ 289 }  = 1

See attachment for the graph

<u>EXPLANATION</u>

The standard equation of the vertical ellipse with center at the origin is given by

\frac{ {x}^{2} }{ {b}^{2} }  +  \frac{ {y}^{2} }{ {a}^{2} }  = 1

where

{a}^{2}  \:  >  \:  {b}^{2}

The ellipse has its vertices at (0,±17).

This implies that:a=±17 or a²=289

The foci are located at (0,±15).

This implies that:c=±15 or c²=225

We use the following relation to find the value of b²

{a}^{2}  -  {b}^{2}  =  {c}^{2}

\implies \: 289  -  {b}^{2}  =  225

-  {b}^{2}  =  225 - 289

-  {b}^{2}  =  - 64

{b}^{2}  = 64

We substitute into the formula for the standard equation to get:

\frac{ {x}^{2} }{ 64 }  +  \frac{ {y}^{2} }{ 289 }  = 1

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ICE Princess25 [194]

GIVE ME THE ANSWER!!!!!!!!!!!!!!!!!!

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