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finlep [7]
2 years ago
9

Find the volume. Round to nearest hundredth

Mathematics
1 answer:
AlladinOne [14]2 years ago
8 0

Answer:

2pir^2 + 2pirh

2(pi)(3.2)^2+2pi(3.2)(8)

=225.19

=225.2

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Recall the formula for the height of an object with a given initial vertical velocity and Initial height:
yKpoI14uk [10]

Answer: it’s D

Step-by-step explanation:

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2 years ago
Extra points
weqwewe [10]

Answer:

Sale tax rate = 7.5%

Step-by-step explanation:

The book cost $12.95

If you take 12.95 x 0.075 = 0.97125

Round the answerto the hundredth (0.97)

Add the tax, 12.95 + 0.97 = 13.92

5 0
3 years ago
The distance from the origin to the point ​(-24​, 32​) is
Zepler [3.9K]
The Pythagorean theorem tells you that distance is
.. √((-24)^2 +32^2)) = √(576 +1024) = √1600 = 40
6 0
3 years ago
I need you to answer with a, b, c, d
solong [7]

To find the zeros of a quadratic fiunction given the equation you can use the next quadratic formula after equal the function to 0:

\begin{gathered} ax^2+bx+c=0 \\  \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}

For the given function:

f(x)=2x^2-10x-3x=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(2)(-3)}}{2(2)}x=\frac{10\pm\sqrt[]{100+24}}{4}\begin{gathered} x=\frac{10\pm\sqrt[]{124}}{4} \\  \\ x=\frac{10\pm\sqrt[]{2\cdot2\cdot31}}{4} \\  \\ x=\frac{10\pm\sqrt[]{2^2\cdot31}}{4} \\  \\ x=\frac{10\pm2\sqrt[]{31}}{4} \\  \end{gathered}\begin{gathered} x_1=\frac{10}{4}+\frac{2\sqrt[]{31}}{4} \\  \\ x_1=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \end{gathered}\begin{gathered} x_2=\frac{10}{4}-\frac{2\sqrt[]{31}}{4} \\  \\ x_2=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}

Then, the zeros of the given quadratic function are:

\begin{gathered} x=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \\  \\ x_{}=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}

Answer: Third option

8 0
1 year ago
Need help with all of this please
Harrizon [31]

Answer:

Step-by-step explanation:

In a right angled triangle, we have perpendicular, hypotenuse and base.

The hypotenuse is the longest side and opposite to the right angle. the side having 90 degree angle is perpendicular.

Applying formulas we can find the values:

the formulas are : cos (Ф) = Base / hypotenuse

sin (Ф) = Perpendicular / hypotenuse

tan (Ф) = Perpendicular / Base

11. cos z

cos z = Base / hypotenuse

cos z = 12/15

12. cos C

cos C = base / hypotenuse

cos C = 38/45

13. tan C

tan C = Perpendicular/ Base

tan C = 40/30

14. tan A

tan A = Perpendicular/ Base

tan A = 21/20

15. tan C

tan C = Perpendicular/ Base

tan C = 12/35

16. tan X

tan X = Perpendicular/ Base

tan X = 30/40

17. sin Z

Sin Z = Perpendicular / Hypotenuse

sin Z = 35/37

18. sin z = Perpendicular / Hypotenuse

sin z = 30/50

8 0
3 years ago
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