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pshichka [43]
3 years ago
15

As a first step, what must be done to both sides of the equation? -5n - -2 = 27? A) divide by 5 B) subtract 2 C) add 2 D) multip

ly by -5
Mathematics
2 answers:
Naddika [18.5K]3 years ago
8 0
Hi I would like to point out that two negatives equal a posture so that equation should look like -5n+2=27 so now what tou want to do is subtact 2 from both sides you are not dividing because you want to find the value of n
galben [10]3 years ago
7 0
The answer is A) Divide by Five
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For which equations is x = 9 a possible solution? Check all that apply.
ahrayia [7]

Answer: choice 1 and 6

Step-by-step explanation:

just plug in 9 for every X making sure they equal each other.

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2 years ago
In 2005, Lee began working as a nurse anesthetist with a taxable income of $119,000. The Medicare tax was 1.45% and the Social S
maks197457 [2]

Answer:

$7,305.50

Step-by-step explanation:

The computation of the FICA tax pay in 2005 is shown below:

Medicare = 1.45% × $119,000 = $1,722.50

And, Social security tax = 6.2% × 90,000  = $5,580

So, the FICA tax in 2005 is

= Medicare tax + Social security tax

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= $7,305.50

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2 years ago
If the parent function is y = 2x, which is the function of the graph?
natita [175]

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7 0
3 years ago
A manufacturer of processing chips knows that 2\%2%2, percent of its chips are defective in some way. Suppose an inspector rando
kipiarov [429]

The data in the question seems a bit erroneous. I am writing the correct question below:

A manufacturer of processing chips knows that 2%, percent of its chips are defective in some way. Suppose an inspector randomly selects 4 chips for an inspection. Assuming the chips are independent, what is the probability that at least one of the selected chips is defective? Lets break this problem up into smaller pieces to understand the strategy behind solving it.

Answer:

The probability that at least one of the selected chips is defective is 0.0776.

Step-by-step explanation:

The question states that the probability of defective chips is 2% i.e. 0.02. Let p denote the probability of selecting a defective chip so, p = 0.02

An inspector selects 4 chips, which means n=4 and we need to compute the probability that at least one of the selected chips is defective. Let X be the number of defective chips selected. We need to compute P(X≥1) which means either 1, 2, 3 or 4 chips can be defective.

We will use the binomial distribution formula to solve this problem. The formula is:

<u>P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ</u>

where n = total no. of trials

          p = probability of success

          x = no. of successful trials

          q = probability of failure = 1-p

we have n=4, p=0.02 and q=1-0.02=0.98.

We need to compute P(X≥1) which is equal to:

P(X≥1) = P(X=1) + P(X=2) + P(X=3) + P(X=4)

A shorter method to do this is to use the total probability theorem:

P(X≥1) = 1 - P(X<1)

          = 1 - P(X=0)

          = 1 - ⁴C₀ (0.02)⁰(0.98)⁴⁻⁰

          = 1 - (0.98)⁴

          = 1 - 0.9224

P(X≥1) = 0.0776

4 0
3 years ago
Rewrite 5/6 with the denomintaior of 12
svp [43]
To change 5/6 to a fraction with a denominator of 12, you need to do one step.  Since 12 is a multiple of 6 (meaning that it can be multiplied by 6 and another number), you multiply 5/6 by 2 to get 10/12. 10/12 is your answer.
3 0
2 years ago
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