Ask question

Ask question

All categories

3 years ago

6

plzzzz help! Determine the truth value of the statement. If three sides of one triangle are equal to three sides of another tria

ngle, then the triangles are congruent. True False

2 answers:

Tamiku [17]3 years ago

5 0

True that would make it congruent

lions [1.4K]3 years ago

5 0

True. Congruent means the triangles are the same size.

You might be interested in

A scale drawing of a rectangular park is 5 inches wide and 7 inches long. The actual park length is 280 yards. What is the width

Anastaziya [24]

Answer:

56,000

Step-by-step explanation:

7 inches → 280 yards

1 inch → 280 ÷ 7 = 40 yards

5 inches → 40 x 5 = 200 yards

Area = 280 x 200 = 56 000 yards

3 0

3 years ago

Read 2 more answers

What is standard form in slope

tatyana61 [14]

Answer:

The standard form of an equation is Ax + By = C. In this kind of equation, x and y are variables and A, B, and C are integers. We can convert a point slope equation into standard form by moving the variables to the left side of the equation.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Circle P is described by the equation (x−1)2+(y+6)2=9 and circle Q is described by the equation (x+4)2+(y+14)2=4. Select from th

xeze [42]

Answer:

(a) Circle Q is 9.4 units to the center of circle P

(b) Circle Q has a smaller radius

Step-by-step explanation:

Given

$P:(x - 1)^2 + (y + 6)^2 = 9$

$Q:(x + 4)^2 + (y + 14)^2 = 4$

Solving (a): The distance between both

The equation of a circle is:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$Center: (h,k)$

$Radius:r$

P and Q can be rewritten as:

$P:(x - 1)^2 + (y + 6)^2 = 3^2$

$Q:(x + 4)^2 + (y + 14)^2 = 2^2$

So, for P:

$Center = (1,-6)$

$r = 3$

For Q:

$Center = (-4,-14)$

$r = 2$

The distance between them is:

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

Where:

$Center = (1,-6)$ --- $(x_1,y_1)$

$Center = (-4,-14)$ --- $(x_2,y_2)$

So:

$d = \sqrt{(1 - -4)^2 + (-6 - -14)^2$

$d = \sqrt{(5)^2 + (8)^2$

$d = \sqrt{25 + 64$

$d = \sqrt{89$

$d = 9.4$

Solving (b): The radius;

In (a), we have:

$r = 3$ --- circle P

$r = 2$ --- circle Q

By comparison

$2 < 3$

<em>Hence, circle Q has a smaller radius</em>

4 0

3 years ago

Which equations represent the asymptotes of the hyperbola?

makvit [3.9K]

Answer:

see below

Step-by-step explanation:

The equation of the hyperbola can be written as ...

((x -h)/a)² -((y -k)/b)² = 1

This has asymptotes ...

(x -h)/a ± (y -k)/b = 0

Solving for y, we have ...

y = ±(b/a)(x -h) +k

Filling in the given values a=6, b=8, h=1, k=2, we have ...

y = ±8/6(x -1) +2

$y=\dfrac{\pm4x\mp4+6}{3}\\\\\boxed{y=\dfrac{4x+2}{3}\ \text{and }y=\dfrac{10-4x}{3}}$

4 0

4 years ago

kkurt [141]

1) Y intercept is -5. x is about1.25

2) Y intercept is +2. X is -2

3) Duplicate question

6 0

4 years ago

Read 2 more answers