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Levart [38]
3 years ago
12

Will give brainiest answer, I need step-by-step answer

Mathematics
1 answer:
Korvikt [17]3 years ago
6 0

Answer: Choice A

The volume expression is 4/3 times pi times (3x)^3

===================================================

The volume of a sphere is found through the formula

V = (4/3)*pi*r^3

so we start with the fraction 4/3, multiply it with pi, and then multiply it with r^3

In this case, the radius is r = 3x because this is half of the diameter d = 6x

We simply replace the r with 3x in that formula above

V = (4/3)*pi*r^3

V = (4/3)*pi*( r )^3

V = (4/3)*pi*(3x)^3 ... replace r with 3x

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HELPPPPPPPPPPPPPPPPPPPPPPPP
mixer [17]

Answer:

x = 20

Step-by-step explanation:

The angles shown are alternate exterior angles.

Alternate exterior angles are congruent

This means that 46 must equal 3x - 14

Note that we've just created an equation that we can use to solve for

We now use the equation to solve for x

3x - 14 = 46

add 14 to both sides

3x - 14 + 14 = 46 + 14

simplify

3x = 60

Divide both sides by 3

3x / 3 = x

60 / 3 = 20

We get that x = 20

4 0
2 years ago
Add x^3 - 4x^2 + 1 to 3x^2 + x <br> Show Your work!
Sladkaya [172]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \: (x {}^{3}  - 4x {}^{2}  + 1) + (3 {x}^{2}  + x)

\qquad \sf  \dashrightarrow \:  {x}^{3}  - 4 {x}^{2}  + 1 + 3 {x}^{2}  + x

\qquad \sf  \dashrightarrow \:  {x}^{3}  - 4 {x}^{2}  + 3x {}^{2}  + x + 1

\qquad \sf  \dashrightarrow \:  {x}^{3}  -  {x}^{2}  + x + 1

6 0
2 years ago
If an integer m is divisible by both 10 and 12, then it must also be divisible by which of the following?
Murrr4er [49]

Answer:

20

Step-by-step explanation:

an integer m is divisible by both 10 and 12

Lets write the prime factor for each number

the prime factor for 10 is 5,2

the prime factor for 12 is 3,2,2

Now take the product of the  prime factors that are not in common and also in common5 \cdot 3 \cdot 2 \fdot 2= 60

60 is divisible  by 20

so answer is 20

3 0
3 years ago
Expand (x-y)^5 using pascal’s triangle
mina [271]

Hello from MrBillDoesMath!

 

Answer:

x^5 - 5 x^4 y + 10 x^3 y^2 - 10 x^2 y^3 + 5 x y^4 - y^5


Discussion:

Pascal's triangle looks like this (up to 6 rows)

    1  

   1 1  

  1 2 1  

 1 3 3 1  

1 4 6 4 1  

1  5 10 10 5 1


The last row contains the constant multipliers in the equation. The terms in the expansion alternate in sign.


Thank you,

MrB

7 0
2 years ago
If the lengths of the right triangle are 7 and 8 what is the approximate hypotenuse
ANEK [815]
<h3>Answer:</h3>

c=√a²+b²

=√7²+8²

<h3> C ≈10.63015 or 10.6</h3>

Hope this helps! <3

4 0
3 years ago
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