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Genrish500 [490]
3 years ago
13

Will this happen in avenger 4?

Mathematics
1 answer:
Marizza181 [45]3 years ago
4 0

In chess, the Endgame is where you sacrafice pawns, or in this case, minor characters in order to get a powerful piece back. You can leave some pawns in battle while regaining power pieces. The pawns sacraficed were Peter, Stephen, Bucky, Drax, T'challa. Mantis, etc. While leaving behind two pawns: Nebula, and Bruce Banner. Normally I like to think of the Hulk as a Rook, but since he's completely useless at the moment, he's a pawn. Nebula's fairly worthless, so she's a pawn. Thanos is playing with all power pieces and one pawn: Gamora. He sacraficed his pawn in order to complete his queen equivilence: the gauntlet. Now he's playing with all power pieces, while the Avenger's have sacraficed their pawns in order to get their queen: Captain Marvel, who in turn will wage war on Thanos only to find that a pawn has made it across the board and turned into the Hulk, and fights side by side the original Avengers to get the soul stone, revive Tony, who probably dies, get their friends home, welcome new friends, and kill Thanos.

Sorry about the rambling. I'm not even sure if I got to the point.

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5 0
2 years ago
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A TRAFFIC LIGHT IS RED FOR 38 SECONDS YELLOW FOR 10 SECONDS AND GREEN FOR ONE MINUTE AND TWELVE SEONDS. IN A CONSTANTLY REPEATIN
morpeh [17]
The chance is 3/5 that the light will be green.

Added together the total seconds for the traffic light to complete the cycle is 120 (38+72 (1 min and 12 sec) +10.

And the green light proportion is: 72/120

We simplify by dividing by 12, which is a factor and we get: 6/10 that simplifies to 3/5.

Hope this helps!
7 0
3 years ago
144=12x <br> 45 =4x-27 <br> 2x-2=14 <br> 12x=44-10x does any one kno these questions?
Free_Kalibri [48]

Hello russell6333!

\huge \boxed{\mathfrak{Question} \downarrow}

Solve for x.

  1. 144 = 12x
  2. 45 = 4x - 27
  3. 2x - 2 = 14
  4. 12x = 44 - 10x

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

1) \:  \:  \: 144 = 12x \\  \frac{144}{12}  = x \\ \boxed{ \boxed{  \bf12 = x}}

__________________

2) \:  \:  \: 45 = 4x - 27 \\ 45 + 27 = 4x \\ 72 = 4x \\  \frac{72}{4}  = x \\  \boxed{ \boxed { \bf18 = x }}

__________________

3) \:  \:  \: 2x - 2 = 14 \\ 2x = 14 - 2 \\ 2x = 12 \\ x =  \frac{12}{2}  \\ \boxed{  \boxed{ \bf \: x = 6}}

__________________

4) \:  \:  \: 12x = 44 - 10x \\ 12x + 10x = 44 \\ 22x = 44 \\ x =  \frac{44}{22}  \\  \boxed{\boxed{  \bf \: x = 2}}

__________________

<h3><u>NOTE </u><u>:</u><u>-</u></h3>
  • To solve questions of these sorts, bring all the terms to one side & simplify it leaving x alone in the other side of the equation (other side of the equal to sign). After simplification you'll get the value of x.
  • Remember that the signs & operations will change when you bring a term to the other side of the equation.
  • So, addition will become subtraction, subtraction will become addition, multiplication will become division & division will become multiplication.

__________________

Hope it'll help you!

ℓu¢αzz ッ

8 0
3 years ago
Read 2 more answers
Calculate the gradient of the straight line which joins A(2,-3) and B(6,9)<br>​
Pie

Answer:

Gradient: m = 3

Step-by-step explanation:

m = change in y/change in x

m = \frac{Y2-Y1}{X2-X1}

m = \frac{9-(-3)}{6-(2)}

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5 0
3 years ago
Part B what are the probabilities of each outcome in the sample space? select all that apply
zepelin [54]

Answer:

C, D, and E are correct

Step-by-step explanation:

p(2)= 1/6; p(3)= 1/6; p(4)= 1/6; 1/6=1/6=1/6

p(1)= 3/6; 3/6=1/2

p(4) = 1/6; There are six sections and one section is labeled<em> '4' </em>

<em />

Hope this helped! ;p

7 0
3 years ago
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