Y=2/3x+2/3 bc slope is 2/3 and 4-2/4-1=2/3
Answer:
Choice D
Step-by-step explanation:
For this one I would find if the point lands on the line.
<em><u>Choice A:</u></em>
What we have to do is to plug in -4 for x and 4 for y.

The point is not on this line so this cannot be it.
<em><u>Choice B:</u></em>
We pug what we know again.

The point is not on this line so it can't be it.
<em><u>Choice C:</u></em>
We pug in what we know again.

The point is not on this line so it can't be it.
The next one has to be it, but we'll check it just in case.
<em><u>Choice D:</u></em>
We plug in what we know again.

The point is on this line so this is the line.
Answer: provided in the explanation segment
Step-by-step explanation:
(a). from the question, we can see that since that б is known, we can use standard normal, z.
we are asked to find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error?
⇒ 80% confidence interval for the average weight of Allen's hummingbirds is given thus;
x ± z * б / √m
which is
3.15 ± 1.28 * 0.32/√10
= 3.15 ± 0.1295 = 3.0205 or 3.2795
(b). normal distribution of weight (c) б is known
(c). option (a) and (e) are correct
(d). from the question, let sample size be given as S
this gives';
1.28 * 0.32/√S = 0.15
√S = (1.28 * 0.32) / 0.15 = 2.73
S = 7.4529
cheers i hope this helps
The decimal number used to represent 5 out of 100 missed on her test is 0.95.