Question

you inherit $10,000 with the stipulation that you for the first year the money must be invested in two stocks paying 6% and 11% annual interest respectively. How much should be invested?

Answer 1

Answer:

At 6% $3,529.412 will be invested

At 11% $6,470.588 will be invested

Explanation:

Let x be the investment for 6% stock

And (10,000-x) is the investment it 11% stock

Let I be interest earned on both investments.

Using the formula

Principal(p)= Interest(I)*Rate(r)*Time(t)

p/RT= I

So considering both investments

x/(6%*1)= (10,000-x)/(11%*1)

x/0.06= (10,000-x)/0.11

Cross-multiply

0.11x= 0.06(10,000-x)

0.11x= 600- 0.06x

Rearranging

0.11x+ 0.06x= 600

0.17x= 600

x= 600/0.17= 3,529.412 amount invested at 6%

Amount invested at 11%= 10,000-3,529.412

= 6,470.588