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boyakko [2]
3 years ago
10

Please help me on #37. I know for A you would use the quadratic equation but I got the wrong answer.

Mathematics
1 answer:
ozzi3 years ago
6 0
Δ = (8i)^2 - 4*(-25) => Δ = -36 +100 => Δ = 64 => x1 =(-8i + 8)/2 => x1 = -4i +4;
x2 = (-8i - 8)/2 => x2 = -4i-4; in this case, your solutions are complex conjugates.
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Which expression is a factor of 9r^2-4r+1
faltersainse [42]

Answer:

There are no real factors for this.

Step-by-step explanation:

We could answer this either by checking each listed expression to see whether it is a factor of 9r^2-4r+1, or

We could take the coefficients of 9r^2-4r+1, determine the quantity b²-4ac (called the 'discriminant') and draw a conclusion based upon whether the discriminant is -, + or 0.

Let's use the 2nd approach.

Here, a = 9, b = -4 and c = 1.

Then the discriminant is b²2 - 4ac, or (-4)² - 4(9)(1), or 16 - 36.

Since 16 - 36 is negative, we conclude that this 9r^2 - 4r + 1 has NO REAL FACTORS.

6 0
3 years ago
What is the median number of points scored by the two players. WILL GIVE BRAINLY.
velikii [3]

Answer:

11

Step-by-step explanation:

5 0
3 years ago
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Craig started the summer with 10 freckles. The number of freckles, F, has doubled each week, W, since summer began. Which equati
mixer [17]

Answer:

The answer to your question is letter D

Step-by-step explanation:

Letter A. It is not possible because it is necessary to considers the variable (number of weeks)and this option does not consider it.

Letter B. It is not possible besides it consider the number of weeks the results do not correspond with the conditions given.

Example: for week 1, the number of freckles is 10 + 2¹ = 10 + 2 = 12, and the number of freckles must be 20.

Letter C. It is incorrect because the numbers of freckles do not correspond with the conditions.

Example:   week 2    f = 2(10) ² = 2(100) = 200, it is higher than the expected.

Letter D. This is the correct answer because it satisfied the conditions given.

4 0
3 years ago
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(5t^3)^-4<br><br> 1. 625/t^12<br> 2. 20/t^7<br> 3. 1/625t^12<br> 4. 1/20t^7
rusak2 [61]

Answer:

\large\boxed{3.\ \dfrac{1}{625t^{12}}}

Step-by-step explanation:

\text{Use}\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^{-n}=\dfrac{1}{a^n}\\---------------\\\\(5t^3)^{-4}=\dfrac{1}{(5t^3)^4}=\dfrac{1}{5^4(t^3)^4}=\dfrac{1}{625t^{(3)(4)}}=\dfrac{1}{625t^{12}}

4 0
3 years ago
What do you get when you round 490.625 to the nearest tenth
VARVARA [1.3K]

Answer:

When you round 490.625 to the nearest tenth its 490.6.

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3 years ago
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