Answer:
x = 10, y = 5
Step-by-step explanation:
Substitute the second equation into the x value of the first equation.
-4x + 11y = 15
-4(2y) + 11y = 15
-8y + 11y = 15
3y = 15
y = 5
Now substitute the y value into an original equation.
x = 2y
x = 2(5)
x = 10
Answer:
The answer is below
Step-by-step explanation:
a) If O(x, y) is the midpoint between two points X(x₁, y₁) and Y(x₂, y₂)m then the coordinates of O is:
x = (x₁ + x₂)/2; y = (y₁ + y₂) / 2
Since M(x, y) is the midpoint of AB, then the coordinates of M is:
x = (0 + 5) / 2 = 2.5; y = (1 + 0)/2 = 0.5
M = (2.5, 0.5)
b) The center of gravity is gotten by finding the average of the x coordinates and the y coordinates of the vertices of the triangle.
Let O(x, y) be the center of gravity of triangle ABC, hence;
x = (0 + 5 + 4) / 3 = 3
y = (1 + 0 + 2) / 3 = 1
O = (3, 1)
Answer:
The correct answer is:
Ken will have run 3 laps and Hamid will have run 4.
Explanation:
To find this, we first find the number of seconds that will have passed when they meet again. We use the LCM, or least common multiple, for this. First we find the prime factorization of each number:
80 = 10(8)
10 = 5(2)
8 = 2(4)
4 = 2(2)
80 = 2(2)(2)(5)(2)
60 = 10(6)
10 = 5(2)
6 = 2(3)
60 = 2(2)(3)(5)
For the LCM, we multiply the common factors by the uncommon. Between the two numbers, the common factors are 2, 2 and 5. This makes the uncommon 2, 2, and 3, and makes our LCM
2(2)(5)(2)(2)(3) = 240
This means every 240 seconds they will both be at the start line.
Since Ken completes a lap in 80 seconds, he completes 240/80 = 3 laps in 240 seconds.
Since Hamid completes a lap in 60 seconds, he completes 240/60 = 4 laps in 240 seconds.
<h2><em>Result :</em></h2>
- <em>Won</em><em> </em><em>=</em><em> </em><em>50</em><em>%</em>
- Won = 50%<em>Draw</em><em> </em><em>=</em><em> </em><em>33</em><em> </em><em>1</em><em>/</em><em>3</em><em>%</em>
- Won = 50%Draw = 33 1/3%<em>Lost</em><em> </em><em>16</em><em> </em><em>2</em><em>/</em><em>3</em><em>%</em>
<h2>
<em>Explanation</em><em> </em><em>:</em></h2>
Express the number of each result as a fraction of the total number of games played and multiply with 100.
- The percentage of the games won is :
<h3>21/42 × 100 = <u>50</u><u>%</u></h3>
- The percentage of the draw games is :
<h3>
14/42 × 100 = 100/3 = <u>33</u><u> </u><u>1</u><u>/</u><u>3</u><u>%</u></h3>
- The percentage of the games lost is :
<h3>
42-21-14/42 × 100 = 7/42 × 100 = 50/3 = <u>16</u><u> </u><u>2</u><u>/</u><u>3</u><u>%</u></h3>
Answer:
9c^7d^13
Step-by-step explanation: