What shape is produced when slicing a right rectangular pyramid perpendicular to the base?

Mathematics

1 answer:

matrenka [14]2 years ago

6 0

C. triangle.
Pyramids are triangles to begin with you’re just making a smaller one

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In a class 26 of students, 17 have a brother and 7 have a sister. There are 4 students who do not have any siblings. What is the

Anni [7]

Number of students = 26
Number of students without siblings = 4
⇒ Number of students with at least one siblings = 26 - 4 = 22

Number of students with brothers = 17
Number of students with sisters = 7
⇒ Number of students with both a brother and a sister = 17 + 7 - 22 = 2

P(student has a brother, given that they have a sister) = 2/7

Answer: 2/7

6 0

3 years ago

What is the distance between the points (2, 10) and (-6, 4) on the coordinate plane?

Galina-37 [17]

It's 3/4 because (y2-y1)/(x2-x1)

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3 years ago

Please help me I'm on a time crunch

Neporo4naja [7]

You multiple it by 20....
1:20
2:40
3:60
4:80
5:100
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8 0

2 years ago

Read 2 more answers

Determine the IQR for this set of data. 12, 13, 14, 15, 17, 18, 19, 19, 22, 23<br> 14 <br> 17.5

VladimirAG [237]

Answer:5

Step-by-step explanation:

4 0

3 years ago

Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes (based on data from an lg sm

GuDViN [60]

Answer: 0.951%

Explanation:

Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.

Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

$P(x = k) = \frac{n!}{k!(n-k)!}p^k (1-p)^{n-k}$

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones).

Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

$P(x \ \textless \ 3) = P(x = 0) + P(x = 1) + P(x = 2)
\\ \indent = \frac{12!}{0!(12-0)!}(0.54)^0 (1-0.54)^{12-0} + \frac{12!}{1!(12-1)!}(0.54)^1 (1-0.54)^{12-1} + \\ \indent \frac{12!}{2!(12-2)!}(0.54)^2 (1-0.54)^{12-2}
\\
\\ \indent = \frac{12!}{(1)(12!)}(0.46)^{12} + \frac{12(11!)}{(1)(11!)}(0.54)(0.46)^{11}+ \frac{12(11)(10!)}{(2)(10!)}(0.54)^2(0.46)^{10}
\\
\\ \indent = (1)(0.46)^{12} + (12)(0.54)(0.46)^{11}+ (66)(0.54)^2(0.46)^{10}
\\ \indent \boxed{P(x \ \textless \ 3) \approx 0.00951836732 }
$

Therefore, the probability that there are fewer than 3 adults are using smartphone is 0.00951 or 0.951%.

5 0

3 years ago