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Fofino [41]
3 years ago
10

the stem and leaf plot shows scores on the math quiz for two classes.how many students in each class scored 85

Mathematics
1 answer:
Ann [662]3 years ago
4 0
<span>The Answer is A - Mrs. James's class, two; Mr Cleveland's class, one 
sorry if this is not what you were looking for
</span>
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I will mark u brainles if you're correct
Virty [35]

9514 1404 393

Answer:

  rules of exponents apply

Step-by-step explanation:

The applicable rules of exponents are ...

  a^-b = 1/a^b

  (a^b)(a^c) = a^(b+c)

__

Applying those rules to the given equation, you get ...

  \left(\dfrac{1}{5}\right)^4\cdot\left(\dfrac{1}{5}\right)^2=5^{-6}\\\\ \left(\dfrac{1}{5^4}\right)\cdot\left(\dfrac{1}{5^2}\right)=5^{-6}\\\\ (5^{-4})(5^{-2})=5^{-6}\\\\5^{-4-2}=5^{-6}\\\\5^{-6}=5^{-6}

6 0
3 years ago
In the first 1/6 hour of a rainstorm, 1/10 inch of rain fell. If the rain continued to fall at the same rate, how much rain fell
DochEvi [55]

Answer:

you should multiply or add

Step-by-step explanation:

5 0
3 years ago
Guys please help me with this question, I’d appreciate it a lot
vredina [299]
The answer is 435 :)
3 0
3 years ago
A sanitation department is interested in estimating the mean amount of garbage per bin for all bins in the city. In a random sam
bekas [8.4K]

Answer:

<em>The   95.7% confidence interval for the expected amount of garbage per bin for all bins in the city</em>

(48.937 , 50.863)

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given data random sample of 46 bins, the sample mean amount was 49.9 pounds and the sample standard deviation was 3.641

<em>The sample size 'n' =46</em>

<em>mean of the sample x⁻ = 49.9</em>

<em>Standard deviation of the sample S = 3.641</em>

<u>Confidence intervals:</u><em>-</em>

<em>The   95.7% confidence interval for the expected amount of garbage per bin for all bins in the city</em>

<em></em>(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha } \frac{S}{\sqrt{n} })<em></em>

<em>Degrees of freedom = n-1  = 46-1 =45</em>

<em>The tabulated value   t₀.₉₆ =   1.794 ( from t-table)</em>

<em></em>(49.9 - 1.794 \frac{3.641}{\sqrt{46} } ,49.9+ 1.794 \frac{3.641}{\sqrt{46} })<em></em>

(49.9 -0.9630 , 49.9+0.9630)

(48.937 , 50.863)

<u>Conclusion:</u>-

<em>The   95.7% confidence interval for the expected amount of garbage per bin for all bins in the city</em>

(48.937 , 50.863)

4 0
3 years ago
Factor the GCF:-12x4y - 9x³y² + 3x²y³ (5 points)
Alinara [238K]

Answer:

 A. 3x^2y(4x2 + 3xy - y^2)

Step-by-step explanation:

 -12(x^4)y - 9x³y² + 3x²y³

 -3x²y(4x² + 3xy - y²)

5 0
2 years ago
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