Irst thought: since he needs 7 3/4 tons, and each load can carry LESS than a ton, he'll need to make MORE than 7 3/4 loads. So when you get your answer, make sure it it passes that common sense test. Next: He's got to divide the 7 3/4 ton total among all those loads, 3/4 ton at a time. So he needs to divide: 7 3/4 divided by 3/4. It will be easier to do the math if we turn 7 3/4 into an improper fraction, which will be 31/4. So we have to divide 31/4 divided by 3/4, which will give us 10, with 1/4 left over, for a total of 10 1/4 loads. BUT: the wording is that each load carries AT MOST 3/4 ton, so he may carry less than that amount in any given load(s). So he needs to do an amount GREATER THAN OR EQUAL TO 10 3/4 loads. For practical purposes, that means he has to fill his truck (at least part way) 11 different times. (Think of it as completely filled the first 10 times, and 3/4 filled on the 11th/final time.)
Answer:
Hi, There!
Your Answer is 
Step-by-step explanation:
Which Equals
Now if you dived the numerator and denominator by 6 you Get...
Therefore, I hope this helps!
Take Care!
Answer:
Simon: 55 hours
Alvin: 70 hours
Theodore: <u>159</u> hours
Total: 284 hours
Step-by-step explanation:
Let A, T, and S stand for the hours worked by Alvin, Simon, and Theodore.
We are told that:
A = S + 15,
T = 3S - 6
and
A + S + T = 284
Note that the first two equations state the value of A and T in terms of S. Let's use them in the third equation, so that we'll have only one unknow:
A + S + T = 284
(S + 15) + S + (3S - 6) = 284
5S + 9 = 284
<em><u>S = 55</u></em>
Now use this value of S in the first two equations to find A and T:
A = S + 15
A = 55 + 15
<u><em>A = 70</em></u>
T = 3S - 6
T = 3*55 - 6
<em><u>T = 159</u></em>
<u></u>
<u>(55 + 70 + 159) = 284</u>
<u></u>
Answer:
Theta=1.57rad, 4.71rad, 0rad, 2π rad, π rad and –π rad
The answer would be *edited* 41
