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natka813 [3]
3 years ago
14

what number I'm I when you divide me by 5, the remainder is 4 I have two digits both digits are odd the sum of my digits is 10

Mathematics
2 answers:
WINSTONCH [101]3 years ago
5 0
I might be wrong but i think 37
Vlada [557]3 years ago
4 0

I beleive the answer is 37.

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An apartment building contains 64 apartments. If 25% of them have a view of the park how many apartments do not have a view of t
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Answer:

48 apartments did not have a view of the park.

Step-by-step explanation:

25% of 64 (total)= 16 (number of people with view)

64 ( total)-16 (# of people with a view)= 48 (number of people without a view)

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D

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In the given right triangle, find the missing length to the nearest tenth.
Jlenok [28]

Answer:

D. 25 ft.

Step-by-step explanation:

To find the missing length of any right triangle, you can use the Pythagorean Theorem (A^2+B^2=C^2) to solve. A and B represent the legs (which we do have) and C represents the hypotenuse (which we are trying to find). Insert our known values into the theorem, and we will get 24^2+7^2=C^2. Now we just do the basic math for the numbers that we have (24^2 is 576<em>;</em><em> </em>7^2 is 49), and that added up would equal to 625. Now, since C is being squared on the other side, we now have to root both sides. On the side where C is, the radical and the square will cancel out each other, leaving us with just C. But, on the side where 625 is, it should root to 25. Since C is by itself now, the number on the other side (25) will be our answer. Therefore, the missing side is 25 feet long.

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4 years ago
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1) Aarush bakes 3 cakes. Each cake uses 2.7 cups of sugar. How much sugar
marshall27 [118]

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8.1 cups of sugar.

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3 x 2.7 = 8.1

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Define the function
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Given that

g(x) = x^3 + x

the inverse g^{-1}(x) is such that

g\left(g^{-1}(x)\right) = g^{-1}(x)^3 + g^{-1}(x) = x

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g\left(f(x)\right) = f(x)^3 + f(x) = x

Differentiating both sides using the chain rule gives

3f(x)^2f'(x) + f'(x) = 1 \\\\ f'(x) \left(3f(x)^2+1\right) = 1 \\\\ f'(x) = \dfrac1{3f(x)^2+1}

Then the derivative of <em>f</em> at 2 is

f'(2) = \dfrac1{3f(2)^2+1} = \boxed{\dfrac14}

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