3 years ago

A triangle ABC has A(1,-4) B(3,-1) C(3,-8).Find the length of the sides AB and AC

Mathematics

1 answer:

mr_godi [17]3 years ago

4 0

Answer:

Step-by-step explanation:

AB= $\sqrt{(1^{2} -3^{2})+((-4)^{2} -(-1)^{2} ) }$

= $\sqrt{7}$

AC= $\sqrt{(3^{2} -1^{2} )+((-8)^{2}- (-4)^{2} )} \\$

= $\sqrt{56}$

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