Question

A triangle ABC has A(1,-4) B(3,-1) C(3,-8).Find the length of the sides AB and AC

Answer 1

Answer:

Step-by-step explanation:

AB=$\sqrt{(1^{2} -3^{2})+((-4)^{2} -(-1)^{2} ) }$

     =$\sqrt{7}$

AC=$\sqrt{(3^{2} -1^{2} )+((-8)^{2}- (-4)^{2} )}$

     =$\sqrt{56}$