1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
telo118 [61]
3 years ago
8

A test consists of 20 problems and students are told to answer any 10 of these questions. In how many different ways can they ch

oose the 10 questions?
Mathematics
2 answers:
Fittoniya [83]3 years ago
4 0

Answer:  The required number of ways is 184756.

Step-by-step explanation:  Given that a test consists of 20 problems and students are told to answer any 10 of these questions.

We are to find the number of different ways in which the students choose 10 questions.

We know that

the number of ways in which r things can be chosen from n different things is given by

N=^nC_r.

Therefore, the number of ways in which students chose 10 questions from 20 different questions is given by

N\\\\=^{20}C_r\\\\\\=\dfrac{20!}{10!(20-10)!}\\\\\\=\dfrac{20\times19\times18\times17\times16\times15\times14\times13\times12\times11\times10!}{10!\times 10\times9\times8\times7\times6\times5\times4\times3\times2\times1}\\\\\\=184756.

Thus, the required number of ways is 184756.

Furkat [3]3 years ago
3 0
We must find UNIQUE combinations because choosing a,b,c,d... is the same as d,c,b,a...etc.  For this type of problem you use the "n choose k" formula...

n!/(k!(n-k)!), n=total number of choices available, k=number of choices made..

In this case:

20!/(10!(20-10)!)

20!/(10!*10!)

184756
You might be interested in
The enrolment of our school is 800. If 35 % are girls
Anvisha [2.4K]

Answer:

a 7/20. B 13/20

Step-by-step explanation:

800 X 35% = 280

280/800=7/20

6 0
2 years ago
Read 2 more answers
Find the volume of the cylinder with a diameter of 12 inches and a height of 10
kati45 [8]

Answer:

360 pi in ^3

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h

We know the diameter is 12 so the radius is 1/2  the diameter

r = d/2 = 12/2 = 6

V = pi (6)^2 * 10

V = pi (36)*10

V = 360 pi in ^3

We can approximate pi by 3.14

V =1130.4 in ^3

Or we can approximate pi by using the pi button

V =1130.973355  in ^3

6 0
3 years ago
What three numbers have a range of 10 and a mean of 13
serious [3.7K]

16,17,6

16-6 is 10 (range)

16+17+6=39

39/3 is 13. (mean)

7 0
3 years ago
The area in square feet of a rectangular field is x^2-100x+2400. The width, in feet is x-40. What is the length, in feet?
sattari [20]

Answer:

x-60

Step-by-step explanation:

You have to factor out the quadratic.

You know that one of the factors is x-40.

To factor:

Find a number that when added to -40, gives you -100, and also when multiplied, gives you 2400.

That such number is -60.

Add an x before it, and you get (x-60)

3 0
3 years ago
I need help in sovling this probelm. simplify (2xyz)^0
Zielflug [23.3K]
Anything raised to the 0 power = 1
5 0
3 years ago
Read 2 more answers
Other questions:
  • Harriet needs to ship a small vase. The box she will use has a volume of 216 cubic inches. If the side lengths are all the same,
    14·1 answer
  • What does this complex fraction equal??? Please help me
    8·1 answer
  • PLEASE HELP MEHHHHHHHH
    11·1 answer
  • I don’t know the answer to 7+x=12 it is pre algebra please help me
    11·2 answers
  • Solve.<br> 12/n - 1 = 10/n + 3<br><br> A. n = -18<br> B. n = -23<br> C. n = -30<br> D. n = -46
    14·1 answer
  • Consider the points plotted on the number line shown.
    9·2 answers
  • - Aidan buys used bicycles, fixes them up, and sells them. His average cost to buy and fix each bicycle is $27. He also incurred
    12·1 answer
  • Help please need answer soon
    8·1 answer
  • Which of the following equations has exactly one solution?
    12·2 answers
  • Jason has two bags with 6 tiles each. The tiles in each bag are shown below:
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!