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4 years ago

A center-seeking force related to acceleration is _______ force.

1 answer:

4 0

<span>A center-seeking force related to acceleration is centripetal force. The correct option among all the options that are given in the question is the first option or option "A". It is actually a force acting on a body that is moving in a circular path and its direction is towards the center. I hope the answer has helped you.</span>

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Write the letter below for each fraction in the correct box?

xxTIMURxx [149]

In order from left to right:
D, C, A, B

7 0

2 years ago

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Find the measure of each exterior angle.

devlian [24]

Answer:

The answer is 137 degrees

Step-by-step explanation:

Add up the two angles you know already

93 + 44 = 137

Then you take that number and subtract it from 180 in order to find the other interior angle.

180 - 137 = 43

So angle LKJ is 43 degree

Now to find the exterior angle you take the missing angles measurement

Which is 43 and subtract it from 180 to get 137

7 0

3 years ago

Complete the factorization of 4x2 – 9.

Nastasia [14]

Your Answer would be:

4x2<span> – 9 = (2x - 3)(2x + 3)
</span>
Hope this helps!

4 0

3 years ago

Read 2 more answers

Can anyone help me?pls

Mama L [17]

Answer/Step-by-step explanation:

Given:

C = right angle = 90°

BC = a = ?

AB = c = 12

AC = b = 9

Required:

a, <A, and <B

Solution:

✔️Find a using Pythagorean Theorem:

a = √(c² - b²)

a = √12² - 9²) = √63

a = 7.93725393 = 8 (nearest whole number)

✔️Find A by applying trigonometric ratio:

Thus,

Reference angle = A

Hypotenuse = 12

Adjacent = 9

Therefore,

$cos(A) = \frac{adj}{hyp} = \frac{9}{12}$

$cos(A) = 0.75$

$A = cos^{-1}(0.75)$

m<A = 41° (nearest whole number)

✔️Find B:

m<B = 180 - (90 + 41) (sum of interior angles of triangle)

m<B = 49°

8 0

3 years ago

Please help. This is a question on my final exam.

GarryVolchara [31]

The best option here is option B.

6 0

3 years ago