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musickatia [10]
3 years ago
13

Allows a service provider organization to own and manage the infrastructure (including computing, networking, and storage device

s) with tenant organizations by accessing slices of shared hardware resources via the Internet..1. Service portfolio2. Verticle Market Integration3. Voluntary Liquidation4. Public Cloud Computing
Computers and Technology
1 answer:
djverab [1.8K]3 years ago
7 0

Answer:

The answer is "Public Cloud computing".

Explanation:

It is a type of technology that focusing on domain-specific resources rather than using dedicated servers or intelligent machines. All services are provided as well as used throughout the Network and per user are paid, and certain options were wrong which can be described as follows:

  • In option 1, it is used to describe the details, it doesn't store data.
  • In option 2, It is used in the organization.
  • In option 3, It is used for courts or legal documentations.
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Privacy, anonymity, and freedom of expression are all interrelated.
Andre45 [30]

Answer:

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Explanation:

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3 years ago
Which is the correct formula to add the values in cells A1 and B1?
arlik [135]
I'm assuming you are referring to Excel. There are a few ways to add A1 and B1.

First you could use '=SUM(A1+B1)'

You could also use '=SUM(A1:B1)' which adds the values of all the cells between A1 and B1, but since they are next to each other, this would work.

You could also use '=SUM(A1,B1)' where you list all the cells you want to add with commas in between.
7 0
3 years ago
Read 2 more answers
We are building a word processor and we would like to implement a "reflow" functionality that full-justifies text.Given a maximu
adoni [48]

Answer:

The code is given below in Java with appropriate comments

Explanation:

Reflow is an function which helps you to justify your functionality

You need to input a string array and the max width and you will get the

output in a list(string).

public List<String> Reflow(String[] input, int width) {

   List<String> result = new ArrayList<String>();

 

   if(input==null || input.length==0){

       return result;

   }

 

 

   int count=0;

   int last=0;

   ArrayList<String> list = new ArrayList<String>();

   for(int i=0; i<input.length; i++){

       count = count + input[i].length();

 

       if(count+i-last>width){

           int wl = count-input[i].length();

           int sl = maxWidth-wl;

           int each = 1;

           int el = 0;

 

           if(i-last-1>0){

               each = sl/(i-last-1);

               el = sl%(i-last-1);

           }

 

           StringBuilder sb = new StringBuilder();

 

           for(int k=last; k<i-1; k++){

               sb.append(input[k]);

 

               int ce = 0;

               while(ce<each){

                   sb.append(" ");

                   ce++;

               }

 

               if(el>0){

                   sb.append(" ");

                   el--;

               }

           }

 

           sb.append(input[i-1]);//last input in the line

           //if only one word in this line, need to fill left with space

           while(sb.length()<width){

               sb.append(" ");

           }

 

           result.add(sb.toString());

 

           last = i;

           count=input[i].length();

       }

   }

 

   int lastLen = 0;

   StringBuilder sb = new StringBuilder();

 

   for(int i=last; i<input.length-1; i++){

       count = count+input[i].length();

       sb.append(input[i]+" ");

   }

 

   sb.append(input[input.length-1]);

   int d=0;

   while(sb.length()<maxWidth){

       sb.append(" ");

   }

   result.add(sb.toString());

 

   return result;

}

6 0
3 years ago
In Python write a program that reads a list of integers into a list as long as the integers are greater than zero, then outputs
stealth61 [152]

Answer:

l = []

while True:

 no = int(input())

 if no>0:

   l.append(no)

 else:

   break

print(1)

If this helped consider marking this answer as brainliest. Have a good day.

3 0
2 years ago
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