Answer:
133 fishes
Step-by-step explanation:
Units of food A = 400 units
Units of food B = 400 units
Fish Bass required 2 units of A and 4 units of B.
Fish Trout requires 5 units of A and 2 units of B.
i. For food A,
total units of food A required = 2 + 5
= 7 units
number of bass and trout that would consume food A = 2 x 
= 114.3
number of bass and trout that would consume food A = 114
ii. For food B,
total units of food B required = 4 + 2
= 6 units
number of bass and trout that would consume food B = 2 x 
= 133.3
number of bass and trout that would consume food B = 133
Thus, the maximum number of fish that the lake can support is 133.
Answer:
Medium
Step-by-step explanation:
The computation is shown below:
The cost for the small and medium bag is shown below:
As we know that
1kg = 1000g
So 3kg = 3000g
Now for small bags
= 0.95 ÷ 250 × 3000
= £11.40
For medium bags
= £1.80 ÷ 500 × 3000
= £10.80
So here the medium bag would represent the better value
8(4n + 13) = 6n
Use distributive property so :8 (4n) = 32n and 8(13) = 104
32n + 104 = 6n
Subtract 32n from each side and you will get:
104 = 26n
then you divide each side by 26 and your answer will be:
n = 4
Answer:
- 50 ft by 75 ft
- 3750 square feet
Step-by-step explanation:
Let x represent the length of the side not parallel to the partition. Then the length of the side parallel to the partition is ...
y = (300 -2x)/3
And the enclosed area is ...
A = xy = x(300 -2x)/3 = (2/3)(x)(150 -x)
This is the equation of a parabola with x-intercepts at x=0 and x=150. The line of symmetry, hence the vertex, is located halfway between these values, at x=75.
The maximum area is enclosed when the dimensions are ...
50 ft by 75 ft
That maximum area is 3750 square feet.
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<em>Comment on the solution</em>
The generic solution to problems of this sort is that half the fence (cost) is used in each of the orthogonal directions. Here, half the fence is 150 ft, so the long side measures 150'/2 = 75', and the short side measures 150'/3 = 50'. This remains true regardless of the number of partitions, and regardless if part or all of one side is missing (e.g. bounded by a barn or river).
Answer:
See below
Step-by-step explanation:
The first two questions are slope = 0
a horizontal line has zero slope
slope = rise/run = 0 / run = 0
Greatest y value is + 4 from x = 3 to 4
the least y value is -3 fro x = -4 to -3
