Question

1.What is the equation of the line perpendicular to  that passes through ? Write your answer in slope-intercept form. Show your work.

Answer 1

Answer:

1. Use a compass to make arc marks which intersect above and below then connect.

2. $y=\frac{1}{3}x + 2$

Step-by-step explanation:

1. To construct a perpendicular line, use a compass to draw arc marks from one end of the segment through point P. Then repeat this again at the other end. This means at point P there will be two intersecting arc marks. Repeat the process down below with the same radius as used above. Then connect the two intersections.

2. The point slope form of a line is $(y-y_1)=m(x-x_1)$ where $x_1=-3\\y_1=1$. We write  

$(y-1)=m(x--3)\\(y-1)=m(x+3)$  

Since the line is to be perpendicular to the line shown it will have the negative reciprocal to the slope of the function 3x+y =-8. To find m, rearrange the function to be y=-8-3x. The slope is -3 and the negative reciprocal will be 1/3.

$(y-1)=\frac{1}{3}(x+3)$  

Simplify for slope intercept form.

$(y-1)=\frac{1}{3}(x+3)\\(y-1)=\frac{1}{3}x+1\\y=\frac{1}{3}x + 2$