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Nadusha1986 [10]
3 years ago
14

Lilli jogs 1/2 mile in 1/10 hour. What is Lilli's rate in miles per hour?

Mathematics
2 answers:
liraira [26]3 years ago
3 0
If her mileage is half a mile in 6min (0.1h)
her pace would be 5mph
ValentinkaMS [17]3 years ago
3 0
Hello there
Rate (speed) = Distance / Time
                      = 1/2 / 1/10
                      = 5 miles / hour

Hope this helps :))

~Top
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Rafael wants to earn at least $45 trimming trees. He charges $8 per hour and pays $3 in equipment fees. What are the possible nu
pshichka [43]

Answer:

6\leqr

Step-by-step explanation:

45\leq8r-3

48\leq8r

6\leqr

8 0
3 years ago
Evaluate the following integral in cylindrical coordinates triple integral 1/(1+x^2+y^2) dzdxdy z=0..2 y=0..square root(1-x^2) x
sertanlavr [38]

In cylindrical coordinates, we take

x=r\cos\theta

y=r\sin\theta

z=z

so that \mathrm dx\,\mathrm dy\,\mathrm dz=r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz.

We have

1+x^2+y^2=1+r^2

and the integral is

\displaystyle\int_0^2\int_0^\pi\int_0^1\frac r{1+r^2}\,\mathrm dr\,\mathrm d\theta\,\mathrm dz=\frac{\ln2}2\int_0^2\int_0^\pi\mathrm d\theta\,\mathrm dz=\boxed{\pi\ln2}

8 0
3 years ago
PLEASE HELPPPP
Studentka2010 [4]

Answer:

1774.67π mm³

Step-by-step explanation:

Please find attached to this question, the required diagram.

From the question, we are told we have a spherical mold.

We would find the volume of a spherical mold using the formula for the volume of a sphere.

The volume of a sphere is calculated as : 4/3πr³

From the attached diagram, we are given the Diameter do the spherical mold as: 22mm

Radius of the spherical mold = Diameter ÷ 2 = 22mm÷ 2 = 11mm

The volume of the spherical mold = 4/3 × π × 11³

= 1774.6666667π mm³

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5 0
3 years ago
The below shows the cost of items sold at Luke's electronics. Which two items would represent the ratio 3:1
Ugo [173]
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6 0
2 years ago
A survey was conducted that asked 1002 people how many books they had read in the past year. results indicated that x overbar eq
Shalnov [3]
The confidence interval would be (10.44, 12.16).  This means that if we take repeated samples, the true mean lies in 90% of these intervals.

To find the confidence interval, we use:
\overline{x} \pm z*(\frac{\sigma}{\sqrt{n}})

We first find the z-value associated with this.  To do this:
Convert 90% to a decimal:  90% = 90/100 = 0.9
Subtract from 1:  1-0.9 = 0.1
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Subtract from 1:  1-0.05 = 0.95

Using a z-table (http://www.z-table.com) we see that this is directly between two z-scores, 1.64 and 1.65; we will use 1.645:

11.3 \pm 1.645*(\frac{16.6}{\sqrt{1002}})
\\
\\11.3 \pm 0.86
\\(11.3-0.86, 11.3+0.86)
\\(10.44, 12.16)
3 0
3 years ago
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