The volume of a square pyramid is (1/3)(area of base)(height of pyramid).
Here the area of the base is (10 ft)^2 = 100 ft^2.
13 ft is the height of one of the triangular sides, but not the height of the pyramid. To find the latter, draw another triangle whose upper vertex is connected to the middle of one of the four equal sides of the base by a diagonal of length 13 ft. That "middle" is 5 units straight down from the upper vertex. Thus, you have a triangle with known hypotenuse (13 ft) and known opposite side 5 feet (half of 10 ft). What is the height of the pyramid?
To find this, use the Pyth. Thm.: (5 ft)^2 + y^2 = (13 ft)^2. y = 12 ft.
Then the vol. of the pyramid is (1/3)(area of base)(height of pyramid) =
(1/3)(100 ft^2)(12 ft) = 400 ft^3 (answer)
The answer is C because you divide the P so you get KP=AR then you finish the rest
The area of the figure above is 53
Answer:
y< -1
Step-by-step explanation:
Answer:
is standard equation of hyperbola with vertices at (0, ±9) and foci at (0, ±11).
Step-by-step explanation:
We have given the vertices at (0, ±9) and foci at (0, ±11).
Let (0,±a) = (0,±9) and (0,±c) = (0,±11)
The standard equation of parabola is:
From statement, a = 9
c² = a²+b²
(11)² = (9)²+b²
121-81 = b²
40 = b²
Putting the value of a² and b² in standard equation of parabola, we have
which is the answer.
