x = the age of Heather
One half of Heather's age two years from now plus one-third of her age three years ago is twenty years
(x + 2)/2 + (x - 3)/3 = 20
by solving the equation we find
x = 24 years
Answer:
○ 
Step-by-step explanation:
![\displaystyle 6m^3 - 60m^2 + 144m \\ 6m[m^2 - 10m + 24m] \\ \\ \boxed{6m[m - 4][m - 6]}](https://tex.z-dn.net/?f=%5Cdisplaystyle%206m%5E3%20-%2060m%5E2%20%2B%20144m%20%5C%5C%206m%5Bm%5E2%20-%2010m%20%2B%2024m%5D%20%5C%5C%20%5C%5C%20%5Cboxed%7B6m%5Bm%20-%204%5D%5Bm%20-%206%5D%7D)
I am joyous to assist you at any time.
Answer:
D. It is on the angle bisector of ∠BAC
Step-by-step explanation:
Given that point Q is equidistant from AB and AC. This implies that AB and AC forms an angle BAC i.e <BAC. An equidistant point is a point that has the same distance from two different reference points.
Bisection is the process by which a line or angle is divided into two equal parts. A line that passes through the point of division is called a bisector, which is of equal distance to either of the reference points.
Thus by construction, a point that would be of equal distance to AB and AC is on an angle bisector of <BAC. So that point Q is on the angle bisector of <BAC.
400 I think but I’m wrong I don’t give answers to stranger gurl xx
Answer:
Step-by-step explanation:
First, we can transform y = cos(x) to y = 3*cos(x) by stretching the graph vertically by a factor of 3. At x = 0, the y value would now be 3 * 1 = 3 instead of 1 (the stretching would cause all new y-values to be 3 times their original values for any given x).
Now transforming y = 3*cos(x) to y = 3*cos(10*x) will stretch the graph horizontally by a factor of 10 (for any given y value, the new x value corresponding to it is 10 times the original x value).
Finally, to transform y = 3*cos(10*x) to y = 3*cos(10(x-pi)), shift the graph to the right by pi.
