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BigorU [14]
3 years ago
14

Find a, b and h so that f(x)= asin(b(x-h)). Round to two decimal places if necessary.

Mathematics
1 answer:
Natali5045456 [20]3 years ago
6 0

Answer:

The answer is B

Step-by-step explanation:

I'm on edenuity too

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Using the defects method, which of these relationships represents the Law of Cosines if the measure of the included angle betwee
horrorfan [7]
Asked and answered elsewhere.
brainly.com/question/1410592

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Google doesn't recognize the terms "defects method" except in association with various postings of this same problem.
4 0
3 years ago
A woman has 19 coins in her pocket, all of which are dimes and quarters. If the total value of the coins is $ 3.55, how many dim
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13 quarters = 3.25 and 3 dimes =.30 which = 3.55
4 0
3 years ago
The length of a rectangle is 5959 inches greatergreater than twice the width. if the diagonal is 2 inches more than the​ length,
lorasvet [3.4K]

Length: 2w + 59

width: w

diagonal: (2w + 59) + 2  = 2w + 61

Length² + width² = diagonal²

(2w + 59)² + (w)² = (2w + 61)²

(4w² + 118w + 3481) + w²  = 4w² + 122w + 3721

5w² + 118w + 3481 = 4w² + 122w + 3721

w² + 118w + 3481 = 122w + 3721

w² - 4w + 3481 = 3721

w² - 4w - 240 = 0

a = 1, b = -4, c = -240

w = [-(b) +/- \sqrt{(b)^{2}  - 4(a)(c) }]/2(a)

 = [-(-4) +/- \sqrt{(-4)^{2}  - 4(1)(-240) }]/2(1)

   =  [4 +/- \sqrt{(16  + 960) }]/2        

  = [4 +/- \sqrt{(976) }]/2  

  = [2 +/- 4\sqrt{(61) }]/2  

  = 1 +/- 2\sqrt{(61) }

since width cannot be negative, disregard  1 - 2√61

w = 1 + 2√61  ≈ 16.62

Length: 2w + 59  =  2(1 + 2√61) + 59  = 2 + 4√61 + 59  =  61 + 4√61  ≈ 92.24

Answer: width = 16.62 in, length = 92.24 in

7 0
3 years ago
Which of the following is a pair of vertical angles? *
erastovalidia [21]

Answer:

1 and 3, 2 and 4, 5 and 7, and 8 and 65

Step-by-step explanation:

Vertical Angles Congruence Theorem

6 0
3 years ago
56/7 Find the whole number equal to the fraction below
m_a_m_a [10]

Answer:

8

Step-by-step explanation:

56 ÷ 7 = 8

7 0
3 years ago
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