Answer: 0.48
Explanation:
P(A/B) = P(AnB)/P(B) where:
P(A/B) = The probability of event A occurring given that B has occurred.
P(AnB) = The probability of both events A and B occurring.
P(B) = the probability that event B occurs.
So let
P(A) = Probability that the residents of a household own 2 cars.
P(B) = Probability that the annual household income is greater than $25,000.
The question tells us that
P(A/B) = 0.8
Note that: P(A) = 0.7, P(B) = 0.6.
Since we want to work out P(AnB), because it gives the probability that residents have an annual household income over $25,000 and own 2 cars.
We would Rearrange our initial equation to make P(AnB) the subject formula becoming;
P(A/B) = P(AnB)/P(B)
P(B)*P(A/B) = P(AnB)
So, inserting our probabilities into this equation gives:
0.6*0.8 = 0.48
Answer: c. $20,000
Explanation:
The Loss on Realization is monies accrued after assets have been sold off at less than their original value and in Calculating it, the following formula is used,
Loss on realization = Total Capital Balances after payment of liabilities minus - balance
Slotting in the figures therefore we have,
Loss on realization = $40,000 + $70,000 - $80,000
= $30,000 was the total loss on Realization
Seeing as Antonio and Barbara are partners who share income in the ratio of 1:2 we allocate to Barbara as follows,
Barbara = $30,000 * 2/(1+2)
= $20,000
Therefore option C is correct.
Demand supply and market equilibrium will have many changes due to change in the quantity of a supplied product.
Answer:
10.68%
Explanation:
Data provided in the question:
Returns on stock : 12%, 16%, 10%, 19%, 15%, -6%
Now,
Geometric average return on the stock is calculated as:
Geometric average return = 
Thus,
For the given returns on stock
Geometric average return
=![[ (1 + 0.12)\times(1 + 0.16)\times(1 + 0.10)\times(1 + 0.19)\times(1 + 0.15)\times(1 + (- 0.06)) ]^{\frac{1}{6}}-1](https://tex.z-dn.net/?f=%5B%20%281%20%2B%200.12%29%5Ctimes%281%20%2B%200.16%29%5Ctimes%281%20%2B%200.10%29%5Ctimes%281%20%2B%200.19%29%5Ctimes%281%20%2B%200.15%29%5Ctimes%281%20%2B%20%28-%200.06%29%29%20%5D%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D-1)
= ![[ 1.12\times1.16\times1.10\times1.19\times1.15\times0.94 ]^{\frac{1}{6}}-1](https://tex.z-dn.net/?f=%5B%201.12%5Ctimes1.16%5Ctimes1.10%5Ctimes1.19%5Ctimes1.15%5Ctimes0.94%20%5D%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D-1)
= ![[1.8384056768]^{\frac{1}{6}}-1](https://tex.z-dn.net/?f=%5B1.8384056768%5D%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D-1)
= 1.1068 - 1
= 0.1068
or
= 0.1068 × 100%
= 10.68%
Answer:
The answer is below
Explanation:
In a given situation like the one presented in the question, it is believed and expected that three topics in which the Human Resources specialist in the area of the cybersecurity program, would emphasize in the presentation to draw students to this field are the following:
1. It has a high earning potential
2. it is a career field in high demand
3. It is a service to humanity
