Draw out a horizontal line. Place 0 at the center. Then place evenly spaced tick marks on either side of 0. Label the right side of tick marks as 1, 2, 3, ... moving from 0 and going to the right
Label the left side of tick marks -1, -2, -3, ... starting at 0 and moving left
The location -3 on the number line is exactly 3 units away from 0. We start at 0 and move to -3 by moving 3 spots to the left; or we start at -3 and move 3 units to the right to get to 0.
Therefore, the absolute value of -3 is 3
Absolute value on a number line is the distance a number is from 0
The distance is never negative
<span>13⁄41 + 27⁄82 = 26/82 + 27/82 = 53/82
3 5/24 + 6 7/24 + 4 9/24 = 13 20/24 = 13 5/6
</span><span>5 2⁄3 + 29⁄69 + 6 21⁄23 = 5 46/69 + 29/69 + 6 63/69 = 11 138/69 = 13
</span>
<span>3 9⁄10 + 4⁄9 + 7⁄45 + 4 = 3 81/90 + 40/90 + 14/90 + 4 = 7 135/90 = 8 1/2
</span><span>6 – 7⁄15 = 5 15/15 - 7/15 = 5 6/15
</span><span>11 3⁄8 – 7⁄8 = 10 11/8 - 7/8 = 10 4/8 = 10 1/2
</span><span> 7 1⁄6 – 3 4⁄9 = 7 9/54 - 3 18/54 = 6 63/54 - 3 18/54 = 3 45/54 = 3 5/6
</span>
<span>5 3⁄8 – 3 2⁄5 = 5 15/40 - 3 16/40 = 4 55/40 - 3 16/40 = 1 39/40</span>
3y+21+8y
11y+21 is the answer
4x+40-3x-2-x
(4x-3x-x)=4x-4x=0
(40-2)=38
The answer will be 38
<span>Can a Segment have more than one bisector. Yes A segment can have more than one bisector. For every line segment, there is one perpendicular bisector that passes through the midpoint. There are infinitely many bisectors, but only one perpendicular bisector for any segment.</span>
