Answer:
sin(θ)^2 + tan2θ + sin(θ)^2 + cosθsinθ - cos(θ)^2. sinθ.tan2θ - cos(θ)^2 . sinθ - cos(θ)^2 / cosθsinθ
The answer is -6 you substitute the x for -4 and multiply 3•-4=-12 +6 =-6
9514 1404 393
Answer:
B = 6.65 in²
Step-by-step explanation:
The base area (B) is the area of the triangular base of the prism. You already know the sides of that triangle are 3, 5, and 7 inches. The figure shows the altitude to the side length 7 is 1.9 inches. The triangle area formula applies:
A = 1/2bh
A = 1/2(7 in)(1.9 in) = 6.65 in² . . . . area of one triangular base.
Then the area of one base is B = 6.65 in².
__
The lateral area is the product of the perimeter and the height:
LA = Ph = 15(12) = 180 . . . . square inches
The total surface area is the sum of the lateral area and the areas of the two bases.
SA = LA + 2B
SA = 180 in² + 2(6.65 in²) = 193.3 in²
The sum of 14 and 16 is 30.30 times 4 is 120.
<span>(<span>14+16</span>)</span><span>(4)
</span><span>=<span><span>(30)</span><span>(4)</span></span></span><span>=
<span>120</span></span>
Inter portal range of 4th period box plot is higher than the 2nd period of box plot. The 4th period class should get the reward.
<h3>
What is box plot?</h3>
Box plot is the way of representation of data which gives the graphical image of the data set to understand better.
The minimum and the maximum values in the box plot is plotted at the end points.
Given information-
Box plot labeled 2nd period with min at 77, Q1 at 78, median at 89, Q3 at 92, max at 100.
Box plot labeled 4th period with min at 72, Q1 at 82.5, median at 89, Q3 at 96, max at 97. 5.
From the box plot we can see the points as,
- The maximum score of the 2nd period class is 77 and the 4th period class is 72, but this does not show the better performance of the class.
- The maximum score of the 2nd period class is 100 and the 4th period class is 97.5, but this does not show the better performance of the class.
- Median for both the class is same which is 89.
- The inter portal range of the box plot of 4th period is higher than the 2nd period box plot. Thus 4th period class performed better.
Hence, the 4th period class should get the reward. Though the medians are the same, the first and third quadrilles are higher, so the students did better on average than in the 2nd period class.
Learn more about the box plot here;
brainly.com/question/14277132
