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3 years ago

Which of the following statements correctly compared lines a and b

Mathematics

1 answer:

3241004551 [841]3 years ago

8 0

The second one is right

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The perimeter of a television screen is 94 inches it is 17 inches tall how wide is it

Nadya [2.5K]

<h3>Answer: 30 inches</h3>

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Explanation:

x = unknown width

For this rectangle, there are 2 sides of length x, and 2 sides of length 17.

The perimeter is P = 2x+2*17 = 2x+34

Set this equal to the given perimeter (94) and solve for x.

2x+34 = 94

2x = 94-34

2x = 60

x = 60/2

x = 30

The TV is 30 inches wide

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2 years ago

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The cost of Tulip and Roses are 1500LL and 2500LL respectively

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3 years ago

How much sugar syrup would you get by Making 5% sugar syrup using 6g sugar?

kherson [118]

Answer: 120 grams.

Step-by-step explanation:

Let x be the amount of sugar syrup made by 5% sugar syrup using 6g sugar.

Also, 5% =0.05

Therefore, 5% sugar syrup =5% of x = 0.05x

According to the question, we have

$0.05x=6\\\text{Divide 0.05 on the both sides we get}\\\Rightarrow\ x=\frac{6}{0.05}\\\Rightarrow\ x=\frac{600}{5}\\\Rightarrow\ x=120$

Hence, 120 grams sugar syrup is made by 5% sugar syrup of 6g sugar.

5 0

3 years ago

Read 2 more answers

A) (3,2),(2,1)<br><br> B) (3,-2),(-2,1)<br><br> C) (-3,2),(-2,-1)<br><br> D) (-3,-2),(2,-1)

bija089 [108]

Answer:

Step-by-step explanation:

4 0

4 years ago

Question 3 (1 point) Co-60 has a half life of 5.3 years. If a pellet that has been in storage for 26.5 years contains 14.5g of C

Zarrin [17]

Answer:

464 grams.

Step-by-step explanation:

Amount of substance:

The amount of substance after t years is given by an equation in the following format:

$A(t) = A(0)(1-r)^t$

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Co-60 has a half life of 5.3 years.

This means that:

$A(5.3) = 0.5A(0)$

We use this to find r. So

$A(t) = A(0)(1-r)^t$

$0.5A(0) = A(0)(1-r)^{5.3}$

$(1-r)^{5.3} = 0.5$

$\sqrt[5.3]{(1-r)^{5.3}} = \sqrt[5.3]{0.5}$

$1 - r = 0.5^{\frac{1}{5.3}}$

$1 - r = 0.8774$

$A(t) = A(0)(0.8774)^{t}$

If a pellet that has been in storage for 26.5 years contains 14.5g of Co-60, how much of this radioisotope was present when the pellet was put in storage?

We have that $A(26.5) = 14.5$ , and use this to find A(0). So

$A(t) = A(0)(0.8774)^{t}$

$14.5 = A(0)(0.8774)^{26.5}$

$A(0) = \frac{14.5}{(0.8774)^{26.5}}$

[tex]A(0) = 464[tex]

464 grams.

3 0

3 years ago