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tekilochka [14]
3 years ago
8

Which of the following statements correctly compared lines a and b

Mathematics
1 answer:
3241004551 [841]3 years ago
8 0
The second one is right
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The average weight of the largest bone in the inner ear is approximately 0.000109 ounces.drag the tiles to show 0.000109 in scie
VladimirAG [237]

Answer:

it would be 1.09x10^4

Step-by-step explanation:

3 0
4 years ago
What is the mean? Thank you math experts
Ulleksa [173]
<h2>Answer:</h2>

The Mean is simply the average of all the numbers. Meaning(see what I did there):
The answer is D) 49.3

<h2>Step-by-step explanation:</h2>

To find the Mean all you have to do is find the average for all the numbers. That's what a Mean is. So put simply all you have to do is add all the numbers and divide by how many there are.
43+55+51+62+64+38+35+45+51 =
444 / 9 ≈
49.3 or 49.333333333333333333...
~Neo

7 0
2 years ago
I really hope you can see it if you can’t please ask me what it says cause I really need help
soldier1979 [14.2K]

Answer:

1.   20 cm^2

2.  40 cm^2

3.   14 cm^2

4    49 cm^2

Step-by-step explanation:

Area of triangle= 1/2(base)*(height)

Area of rectangle= (base)*(height)

1. 1/2(10)(4)=20

2. (8)(5)=40

3.1/2(4)(7)=14

4. (7)(7)=49

5 0
3 years ago
X ^ (2) y '' - 7xy '+ 16y = 0, y1 = x ^ 4
AfilCa [17]
Given a solution y_1(x)=x^4, we can attempt to find another via reduction of order of the form y_2(x)=x^4v(x). This has derivatives

{y_2}'=4x^3v+x^4v'
{y_2}''=12x^2v+8x^3v'+x^4v''

Substituting into the ODE yields

x^2(x^4v''+8x^3v'+12x^2v)-7x(x^4v'+4x^3v)+16x^4v=0
x^6v''+(8x^5-7x^5)v'+(12x^4-28x^4+16x^4)v=0
x^6v''+x^5v'=0

Now letting u(x)=v'(x), so that u'(x)=v''(x), you end up with the ODE linear in u

x^6u'+x^5u=0

Assuming x\neq0 (which is reasonable, since x=0 is a singular point), you can divide through by x^5 and end up with

xu'+u=(xu)'=0

and integrating both sides with respect to x gives

xu=C_1\implies u=\dfrac{C_1}x

Back-substitute to solve for v:

v'=\dfrac{C_1}x\implies v=C_1\ln|x|+C_2

and again to solve for y:

y=x^4v\implies \dfrac y{x^4}=C_1\ln|x|+C_2
\implies y=C_1\underbrace{x^4\ln|x|}_{y_2}+C_2\underbrace{x^4}_{y_1}

Alternatively, you can solve this ODE from scratch by employing the Euler substitution (which works because this equation is of the Cauchy-Euler type), t=\ln x. You'll arrive at the same solution, but it doesn't hurt to know there's more than one way to solve this.
6 0
4 years ago
Students from grades 11 and 12 in Jason's school were asked to vote for the prom king and queen. Jason surveyed every 12th stude
Ymorist [56]

Answer:

you don't even ask a question here

Step-by-step explanation:

6 0
3 years ago
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