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3 years ago

Which of the following statements correctly compared lines a and b

Mathematics

1 answer:

3241004551 [841]3 years ago

8 0

The second one is right

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The average weight of the largest bone in the inner ear is approximately 0.000109 ounces.drag the tiles to show 0.000109 in scie

VladimirAG [237]

Answer:

it would be 1.09x10^4

Step-by-step explanation:

3 0

4 years ago

What is the mean? Thank you math experts

Ulleksa [173]

<h2>Answer:</h2>

The Mean is simply the average of all the numbers. Meaning(see what I did there):
The answer is D) 49.3

<h2>Step-by-step explanation:</h2>

To find the Mean all you have to do is find the average for all the numbers. That's what a Mean is. So put simply all you have to do is add all the numbers and divide by how many there are.
43+55+51+62+64+38+35+45+51 =
444 / 9 ≈
49.3 or 49.333333333333333333...
~Neo

7 0

2 years ago

I really hope you can see it if you can’t please ask me what it says cause I really need help

soldier1979 [14.2K]

Answer:

1. 20 cm^2

2. 40 cm^2

3. 14 cm^2

4 49 cm^2

Step-by-step explanation:

Area of triangle= 1/2(base)*(height)

Area of rectangle= (base)*(height)

1. 1/2(10)(4)=20

2. (8)(5)=40

3.1/2(4)(7)=14

4. (7)(7)=49

5 0

3 years ago

X ^ (2) y '' - 7xy '+ 16y = 0, y1 = x ^ 4

AfilCa [17]

Given a solution $y_1(x)=x^4$ , we can attempt to find another via reduction of order of the form $y_2(x)=x^4v(x)$ . This has derivatives

${y_2}'=4x^3v+x^4v'$
${y_2}''=12x^2v+8x^3v'+x^4v''$

Substituting into the ODE yields

$x^2(x^4v''+8x^3v'+12x^2v)-7x(x^4v'+4x^3v)+16x^4v=0$
$x^6v''+(8x^5-7x^5)v'+(12x^4-28x^4+16x^4)v=0$
$x^6v''+x^5v'=0$

Now letting $u(x)=v'(x)$ , so that $u'(x)=v''(x)$ , you end up with the ODE linear in $u$

$x^6u'+x^5u=0$

Assuming $x\neq0$ (which is reasonable, since $x=0$ is a singular point), you can divide through by $x^5$ and end up with

$xu'+u=(xu)'=0$

and integrating both sides with respect to $x$ gives

$xu=C_1\implies u=\dfrac{C_1}x$

Back-substitute to solve for $v$ :

$v'=\dfrac{C_1}x\implies v=C_1\ln|x|+C_2$

and again to solve for $y$ :

$y=x^4v\implies \dfrac y{x^4}=C_1\ln|x|+C_2$
$\implies y=C_1\underbrace{x^4\ln|x|}_{y_2}+C_2\underbrace{x^4}_{y_1}$

Alternatively, you can solve this ODE from scratch by employing the Euler substitution (which works because this equation is of the Cauchy-Euler type), $t=\ln x$ . You'll arrive at the same solution, but it doesn't hurt to know there's more than one way to solve this.

6 0

4 years ago

Students from grades 11 and 12 in Jason's school were asked to vote for the prom king and queen. Jason surveyed every 12th stude

Ymorist [56]

Answer:

you don't even ask a question here

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers