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Aleksandr [31]
3 years ago
6

Translation of the DNA sequence AAGCTGGGA would result in /9798699/5fdc1d25?utm_source=registration

Biology
2 answers:
VARVARA [1.3K]3 years ago
5 0
Remember A and T are equal and G and C are equal. Translation is UUCGACCCU! Have a good day! :))
Art [367]3 years ago
5 0

actually it would be a sequence of three amino acids linked by peptide bonds.

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GIVING AWAY 20 POINTS PLEASE HELP ME ASAP!!! THE ANSWER IS NOT A
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The answer is C because, Ecoregions cover relatively large areas of land or water, and contain characteristic, geographically distinct assemblages of natural communities and species.
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2 years ago
Imagine that a brown horse and a white horse cross to produce an offspring whose coat is making up of some brown hairs and some
irina1246 [14]

Answer:

Codominance

Explanation:

So this would either be codominance or incomplete dominance. With incomplete dominance, you tend to get a whole other colour- for example crossing black and white chickens and getting a blue chicken. If you cross brown and white, and get a mix, it must be codominance because both traits are shown.

8 0
3 years ago
The image below shows the life cycle of a plant. Which class does this plant belong to?
Firlakuza [10]

Question: <em>The image below shows the life cycle of a plant. Which class does this plant belong to? </em>

<em>Answer: Gymnosperm</em>

<em>If you look up Gymnosperm Life Cycle of Google, and go to images, you will find a diagram/chart of the Gymnosperm Life Cycle, that matched the picture you gave.</em>

Hope this helps, have a good day. c;

Link to the picture of the diagram below...:

https://www.google.com/search?q=gymnosperm+life+cycle&rlz=1C1GCEB_enUS787US787&source=lnms&tbm=isch&sa=X&ved=0ahUKEwjR46qP1pDfAhUKR6wKHZVIBzQQ_AUIDigB&cshid=1544287366922000&biw=1707&bih=732&safe=active&ssui=on#imgrc=15Qy4QiBWX-1iM:

8 0
3 years ago
Read 2 more answers
Nearly all mammals have seven cervical (neck) vertebrae. This fact implies that
stiks02 [169]
C.all mammal descended from a common ancestor.
3 0
3 years ago
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A man who has male pattern baldness (X^bY) marries a woman who does not carry the allele (X^BX^B). What genotypic ratios would b
JulijaS [17]

Answer:

2X^BX^b:2X^BY

Explanation:

<em>The genotypic ratio of expected of their offspring would be 2</em>X^BX^b<em>:2</em>X^BY<em>.</em>

From the illustration, the genotype of the man with male pattern baldness is X^bY while the genotype of the woman without the baldness allele is X^BX^B.

Crossing the two genotypes in marriage:

                           X^bY   x   X^BX^B

Progeny: X^BX^b    X^BX^b    X^BY       X^BY

<em>Hence, the genotypic ratio of the offspring becomes:</em>

2X^BX^b:2X^BY

7 0
3 years ago
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