Answer:
J
Step-by-step explanation:
Mn=PQ
SAS requires 2 sides and you need to know that they are congruent
Answer:
It represents an infinite cylinder of radius 4.
Step-by-step explanation:
The first thing to notice is that

<u>represents a circle of radius 4</u>, with its center in the origin of a plane yz, of cartesians coordinates.
Starting from here, we have to put the coordinate x, for all values of x, to complete the space R³. <em>This will enlarge this circle we had on the plane, to infinity</em> (positive and negative on the x-axis).
Finally, we have that this region is a cylinder of radius 4, with center in y=0 and z=0, and of infinite length in the x coordinates.
D.
1/5 of 65 is
65 × 1 / 5
65 / 5
= 13
65 and 13 add up to 78.
65 is the highest number out of both numbers.
♧
Answer:

Step-by-step explanation:
we know that
The formula to find the sum is equal to

where
a1 is the first term
an is the last term
n is the number of terms
In this problem we have



substitute the values in the formula
