Which graph represents the inequality y-2x≤1?

Find the inner product for (3,1,4)*(2,8,2) and state whether the vectors are perpendicular.

faltersainse [42]

Good evening ,

Answer:

<h2>•• Inner product = 3×2 + 1×8 + 4×2 = 22</h2><h2 /><h2>•• since 22 ≠ 0 then the vectors are not perpendicular.</h2>

:)

5 0

3 years ago

Read 2 more answers

How did Bill spend longer

JulsSmile [24]

How did bill spend longer .. days ... ? what

7 0

3 years ago

1) After a dilation, (-60, 15) is the image of (-12, 3). What are the coordinates of the image of (-2,-7) after the same dilatio

BARSIC [14]

Answer:

a) k = 5; (-10, -35)

Step-by-step explanation:

Given:

Co-ordinates:

Pre-Image = (-12,3)

After dilation

Image = (-60,15)

The dilation about the origin can be given as :

Pre-Image $(x,y)\rightarrow Image(kx,ky)$

where $k$ represents the scalar factor.

We can find value of $k$ for the given co-ordinates by finding the ratio of $x$ or $y$ co-ordinates of the image and pre-image.

$k=\frac{Image}{Pre-Image}$

For the given co-ordinates.

Pre-Image = (-12,3)

Image = (-60,15)

The value of $k=\frac{-60}{-12}=5$

or $k=\frac{15}{3}=5$

As we get $k=5$ for both ratios i.e of $x$ and $y$ co-ordinates, so we can say the image has been dilated by a factor of 5 about the origin.

To find the image of (-2,-7), after same dilation, we will multiply the co-ordinates with the scalar factor.

Pre-Image $(-2,-7)\rightarrow$ Image $((-2\times5),(-7\times 5))$

Pre-Image $(-2,-7)\rightarrow$ Image $(-10,-35)$ (Answer)

7 0

2 years ago

Please need help in algebra quick

Roman55 [17]

After solving $|8-3p|\geq 2$ we get $p\geq \frac{10}{3}\,\, or\,\,p\leq 2$

So, Option A is correct.

Step-by-step explanation:

We need to solve the expression:

$|8-3p|\geq 2$

For solving, we apply the rule that:

if |u| ≥ a and a > 0 then, u ≤ -a and u ≥ a

Applying the rule:

$|8-3p|\geq 2\\8-3p\leq -2 \,\, and\,\,8-3p\geq 2\\$

$8-3p-8\leq -2-8 \,\, or\,\,8-3p-8\geq 2-8\\-3p\leq -10 \,\, or\,\,-3p\geq -6\\Multiply\,\,both\,\,sides\,\,by\,\,-1 (reverse\,\,the\,\,inequality\\3p\geq 10\,\, or\,\,3p\leq 6\\p\geq \frac{10}{3}\,\, or\,\,p\leq\frac{6}{3}\\p\geq\frac{10}{3}\,\, or\,\,p\leq 2$

After solving $|8-3p|\geq 2$ we get $p\geq \frac{10}{3}\,\, or\,\,p\leq 2$

So, Option A is correct.

Keywords: Absolute rule

Learn more about Absolute rule at:

#learnwithBrainly

5 0

3 years ago

The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s

Effectus [21]

Answer:

a.

i. 0 cm/s

ii. 49183 cm/s

iii. 4188.75 cm/s

iv. -673.8 cm/s

b. Instantaneous velocity is -900 cm/s

Step-by-step explanation:

Upon differentiating s = 5 sin πt + 2 cos πt....................Eqn 1

derivative of sin πt is π cos πt

derivative of cos πt is -π sin πt

Therefore derivative of s = 5 sin πt + 2 cos πt is

5π cos πt - 2π sin πt.................Eqn 2

Substituting [1, 2] cm/s into Eqn 2