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Oduvanchick [21]
3 years ago
8

Help me plz someone first answer=brainliest

Mathematics
1 answer:
pav-90 [236]3 years ago
6 0
What is the question?
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Let f(x) = 4x + 3 and g(x) = 7x − 6. Find the function. f/g (f/g)(x) = Find the domain. (Enter your answer using interval notati
guapka [62]

Answer:

f(x) = 4x + 3 \,,\,\,\,g(x) = 7x-6\\(f/g)(x)=\frac{4x+3}{7x-6}\,,\,\,\,7x-6\neq0\implies x\neq \frac{6}{7}\\\mbox{Domain:}\,\,\,x\in(-\infty,\frac{6}{7}) \cup (\frac{6}{7},+\infty)

4 0
3 years ago
Simplify<br> X2-49<br> Over <br> X2+9x+14
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Answer:

(x-7)/(x+2)

Step-by-step explanation:

(x-7)(x+7)/(x+7)(x+2)

(x-7)/(x+2)

7 0
3 years ago
Lim x → 0 sin3x)/5x^3 -4
JulsSmile [24]
\bf \lim\limits_{x\to 0}\ \cfrac{sin^3(x)}{5x^3}-4&#10;\\ \quad \\\\ \cfrac{sin^3(x)}{5x^3}-4\implies \cfrac{[sin(x)]^3}{5x^3}-4&#10;\\ \quad \\&#10; &#10;&#10;\cfrac{[sin(x)]^3}{x^3}\cdot \cfrac{1}{5}-4&#10;\\ \quad \\&#10;thus&#10;\\ \quad \\&#10;\lim\limits_{x\to 0}\cfrac{[sin(x)]^3}{x^3}\cdot \lim\limits_{x\to 0}\cfrac{1}{5}-4\qquad \boxed{recall \qquad \lim\limits_{x\to 0} \cfrac{sin(x)}{x}\implies 1}&#10;\\ \quad \\&#10;1\cdot \cfrac{1}{5}-4
8 0
3 years ago
Find the midpoint of the line segment whose endpoints are (0,1/2 ) and (0,3/4 ).
Ksivusya [100]
Formula of the midpoint:
x =(x₁+x₂)/2    and y = (y₁+y₂)/2

Plugin the respective value
for A(0,1/2)  and B(0, 3/4)

x= (0+0)/2 = 0
y = (1/2 + 3/4)/2 = 5/8 

Then the midpoint of the line segment whose endpoints are (0,1/2 ) and (0,3/4 ). is M(0, 5/8) or M(0, 0.625)

8 0
4 years ago
Read 2 more answers
A parking space shaped like a parallelogram has a base of 17 feet and a height is 7 feet. A car parked in the space is 6feet lon
kkurt [141]

Answer: 83 square feet of the parking space is not covered by the car.

Step-by-step explanation:

Corrrect question

A parking space shaped like a parallelogram has a base of 17 feet and a height is 7 feet. A car parked in the space is 6feet long and and 6feet wide. How much of the parking space is not covered by the car

Hi, to answer this question we have to calculate the area of both the parking space and the space covered by the car.

Area of a rectangle: height x width

Area of the parking space = 7 x 17 = 119 ft2

Area covered by the car = 6 x6 = 36 ft2

Subtracting the area covered by the car (36) to the parking area (119):

119-36 = 83 ft2

83 square feet of the parking space is not covered by the car.

7 0
3 years ago
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