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3 years ago

Find the inner product for (3,1,4)*(2,8,2) and state whether the vectors are perpendicular.

Mathematics

2 answers:

Irina-Kira [14]3 years ago

6 0

Answer:

6 = no

Step-by-step explanation:

their you go

faltersainse [42]3 years ago

5 0

Good evening ,

Answer:

<h2>•• Inner product = 3×2 + 1×8 + 4×2 = 22</h2><h2 /><h2>•• since 22 ≠ 0 then the vectors are not perpendicular.</h2>

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The ratio of the units digit to the tens digit in a two-digit number is one-half. the tens digit is two more than the units digi

vodomira [7]

Let the first digit of the 2-digit number be x and the second digit be y.
Then the ratio (x/y) equals (1/2). Write a formula for y in terms of x.

The tens digit is 2 more than the units digit. Using the letters x and y, write out the proper equation.

Now solve your two equations simultaneously for x and y.

5 0

3 years ago

What is the value of p?

Alex777 [14]

The answer is since the the angle on the inside of the triangle is 90 degrees by supplementary angles and the other angle that is not p is 47 degree, also by supplementary angles. Thus you take 90+47=137 and subtract it from 180 since that is is the total angle sum of a triangle and you get 43 degrees or answer b

6 0

3 years ago

Read 2 more answers

The system x−6y=4, 3x−18y=4 has no solution.

stealth61 [152]

Ok fist you wanna change your question into a equation so it would turn into x-6 y=4 and 4.3x - 18 y = 4 then multiple both sides and that pups give you 43x - 180 y = 40 and eliminate one variable and I don’t wanna keep explaining but the the answer is

ANSWER: (x , y ) = (- 80 over 13, and - 22 over 13

6 0

2 years ago

A (0, 2) and B (6,6) are points on the straight line ABCD.

elena-14-01-66 [18.8K]

Answer:

(18, 14)

Step-by-step explanation:

We know that C and D lie on the line AB and BC = CD = AB. Then we need to use the distance formula and equation of the line AB to find the other two coordinates.

The distance formula states that the distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ , the distance is denoted by: $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ . Let's find the distance between A and B:

d = $\sqrt{(6-0)^2+(6-2)^2}=\sqrt{6^2+4^2} =\sqrt{36+16} =\sqrt{52} =2\sqrt{13}$

Now say the coordinates of D are (a, b). Then the distance between D and B will be twice of 2√13, which is 4√13:

4√13 = $\sqrt{(6-a)^2+(6-b)^2}$

Square both sides:

208 = (6 - a)² + (6 - b)²

Let's also find the equation of the line AB. The y-intercept we know is 2, so in y = mx + b, b = 2. The slope is (6 - 2) / (6 - 0) = 4/6 = 2/3. So the equation of the line is: y = (2/3)x + 2. Since (a, b) lines on this line, we can put in a for x and b for y: b = (2/3)a + 2. Substitute this expression in for b in the previous equation:

208 = (6 - a)² + (6 - b)²

208 = (6 - a)² + (6 - (2/3a + 2))² = (6 - a)² + (-2/3a + 4)²

208 = a² - 12a + 36 + 4/9a² - 16/3a + 16 = 13/9a² - 52/3a + 52

0 = 13/9a² - 52/3a - 156

13a² - 156a - 1404 = 0

a² - 12a - 108 = 0

(a + 6)(a - 18) = 0

a = -6 or a = 18

We know a can't be negative so a = 18. Plug this back in to find b:

b = 2/3a + 2 = (2/3) * 18 + 2 = 12 + 2 = 14

So point D has coordinates (18, 14).

8 0

3 years ago

Read 2 more answers

Find the nth term of a gp with (a. find term = 5, common ratio = 2

Rina8888 [55]

Step-by-step explanation:

we know,

$tn= a {(r)}^{n - 1} \\ T5 = a {(2)}^{5 - 1} \\ t5 = a \times {2}^{4} \\ = 16a$

Therefore, nth term of a given gp is

16a

7 0

3 years ago