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Fynjy0 [20]
3 years ago
15

How many moles of \ce{Fe2O3}FeX 2 ​ OX 3 ​ will be produced from 27.0 \text{ g}27.0 g27, point, 0, start text, space, g, end tex

t of \ce{Fe}FeF, e, assuming \ce{O2}OX 2 ​ is available in excess?
Chemistry
1 answer:
ira [324]3 years ago
6 0

Answer : The number of moles of Fe_2O_3  produced will be, 0.241 moles.

Solution : Given,

Mass of Fe = 27.0 g

Molar mass of Fe = 56 g/mole

First we have to calculate the moles of Fe.

\text{ Moles of }Fe=\frac{\text{ Mass of }Fe}{\text{ Molar mass of }Fe}=\frac{27.0g}{56g/mole}=0.482moles

Now we have to calculate the moles of Fe_2O_3

The balanced chemical reaction is,

4Fe+3O_2\rightarrow 2Fe_2O_3

From the reaction, we conclude that

As, 4 mole of Fe react to give 2 mole of Fe_2O_3

So, 0.482 moles of Fe react to give \frac{0.482}{4}\times 2=0.241 moles of Fe_2O_3

Thus, the number of moles of Fe_2O_3  produced will be, 0.241 moles.

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