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Tanya [424]
3 years ago
6

Please help me answer this. I think that for the first one the answer is A, but I am not sure. There are two parts to the questi

on.

Mathematics
2 answers:
Ne4ueva [31]3 years ago
6 0
P=(5,4). Q=(7,3). R=(8,6) AND S=(4,1)

PQ = (7-5 , 3-4) =PQ=(2,-1)

RS =(4-8 , 1-6) =RS=(-4 , -5). 4.RS=(-16 , -20)

PQ+4RS = (-16-2 , -19) ; PQ = (-18 , -19)
Anika [276]3 years ago
4 0
Vector PQ=(7-5, 3-4)=(2, -1).  4RS=4 \cdot (4-8, 1-6) = 4 \cdot (-4, -5) = (-16, -20).  So the sum is (-14, -21).

For the second, the magnitude is the square root of the sum of the squares of the components.  This is equal to \sqrt{(-14)^2+(-21)^2} = \sqrt{637}=7\sqrt{13}.
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Answer: 56 / 729

Step-by-step explanation: (4 * 2 * 7) / (9^3)

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3 years ago
A metalworker has a metal alloy that is 15​% copper and another alloy that is 75​% copper. How many kilograms of each alloy shou
lisov135 [29]

48 kilograms of 15 % copper is combined with 72 kilograms of 75 % copper to create 120 kg of a 51​% copper​ alloy

<em><u>Solution:</u></em>

Let "x" be the kilograms of 15 % copper

Then, (120 - x) be the kilograms of 75 % copper

Then, according to question,

"x" kilograms of 15 % copper is combined with (120 - x) kilograms of 75 % copper to create 120 kg of a 51​% copper​ alloy

Thus we frame a equation as:

15 % of x + 75 % of (120 - x) = 51 % of 120

<em><u>Solve the equation for "x"</u></em>

15 \% \times x + 75 \% \times (120-x) = 51 \% \times 120\\\\\frac{15}{100} \times x + \frac{75}{100} \times (120-x) = \frac{51}{100} \times 120\\\\0.15x + 0.75(120-x) = 0.51 \times 120\\\\0.15x + 90 - 0.75x = 61.2\\\\0.6x = 90 - 61.2\\\\0.6x = 28.8\\\\Divide\ both\ sides\ by\ 0.6\\\\x = 48

Thus 48 kilograms of 15 % copper used

Then, (120 - x) = (120 - 48) = 72

Thus, 72 kilograms of 75 % copper is used

4 0
3 years ago
What is a six sided shape called
pashok25 [27]

Answer:

hexagon

Step-by-step explanation:

3 0
3 years ago
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This information tells me that f equals a number and 3 multiplied by the number that f equals is 16.

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7 0
4 years ago
Which function is odd?
ddd [48]
The function is odd if you can replace every x with -x and get the oposite equation
example
if you replace x with -x in y=x^3, then you get -x^3, so therefor the functin is odd


so

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d. we get x^4-4x, nope


answer is B
5 0
3 years ago
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