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Inga [223]
3 years ago
8

What is the area of the shaded region?​

Mathematics
1 answer:
IRINA_888 [86]3 years ago
3 0
20 because of the whole is 40 and the shaded part is by 20 you just take half of 40 and you get 20
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Natali5045456 [20]
Write Answer like this #### degrees C
7 0
3 years ago
The article "Measuring and Understanding the Aging of Kraft Insulating Paper in Power Transformers" (IEEE Electrical Insul. Mag.
givi [52]

Answer:

Step-by-step explanation:

Hello!

You have the data corresponding to 17 observations on the degree of polymerization for paper specimens whose viscosity times concentration fell in a certain range.

a) Boxplot attached.

Box: The 2 quantile (Me) appears to be in the middle of the box, the distance between the 1st quantile and the second quantile appears to be equal than the distance between the 2nd quantile and the 3rd quantile. The mean (black square) is greater than the 2nd quantile. In general, the distribution inside the box appears to be symmetrical (comparing just the Me<X[bar], perhaps slightly right-skewed)

Whiskers: The upper whisker is approximately twice as long as the lower whisker. There are no visible outliers in the data set.

In general, it appears as if the data set is right-skewed.

b) I would be more comfortable with a more symmetrical boxplot, but this one shows enough symmetry to be able to assume that the variable may have a normal distribution.

c) If we assume the normal distribution of the variable, you can use a student t to estimate the true value of the average degree of polymerization of paper:

[X[bar] ± t_{n-1;1-\alpha /2} * \frac{S}{\sqrt{n} }]

95% CI: t_{16;0.975}= 2.120

X[bar]= 438.29

S= 15.14

[438.29 ± 2.120 * \frac{15.14}{\sqrt{17} }]

[430.47;446.03]

With a 95% confidence level, you'd expect the interval [430.47;446.03] to include the true value of the average degree of polymerization of paper.

d) and e)

For these two items, you have to use the calculated CI in c) to decide whether or not there is significant evidence to conclude that two possible values of μ are plausible.

To decide over a hypothesis test using a CI several conditions should be met:

1) The hypothesis has to be two-tailed, and for the same parameter estimated in the interval

2) Both the CI and the Hypothesis test should have complementary levels, this means that if the CI was made using a confidence level of 1 - α= 0.95, then the test should have a significance level of α= 0.05

If these conditions are met, the decision rule is:

If the interval doesn't include the value of the parameter stated in the null hypothesis, then you reject the null hypothesis.

If the interval includes the value of the parameter stated in the null hypothesis, then you do not reject the null hypothesis.

d) μ=440?

Hypothesis:

H₀: μ = 440

H₁: μ ≠ 440

α: 0.05

95% CI: [430.47;446.03]

440 is included in the interval, the decision is to not reject the null hypothesis.

Using a 5% significance level, there is significant evidence to conclude that the population mean of the degree of polymerization of paper is 440.

e) μ=450?

H₀: μ = 450

H₁: μ ≠ 450

α: 0.05

95% CI: [430.47;446.03]

450 is not included in the interval, the decision is to reject the null hypothesis.

At a level of 5%, the decision is to reject the null hypothesis, this means that the population mean of the degree of polymerization of paper is different than 450.

I hope it helps!

3 0
3 years ago
Erica sells bracelets for $2 each. The supplies to make each bracelet costs her $0.75. Let “n” represent the number of bracelet
AysviL [449]

Answer:  1.25n

=======================================================

Explanation:

Erica sells bracelets for $2 each. If she makes and sells n of them, then she gets 2n dollars of revenue.

Making n bracelets cost her a total of 0.75n dollars because each bracelet costs 0.75 dollars, or 75 cents.

Subtract the revenue and cost to get the profit

profit = revenue - cost

profit = 2n - 0.75n

profit = (2-0.75)n

profit = 1.25n

The expression 1.25n means that she earns $1.25 in profit per bracelet sold.

3 0
3 years ago
Which equation matches the graph shown below?
MrRa [10]
Given that the graph shows tha the functión at x = 0 is below the y-axis, the constant term of the function has to be negative. This leaves us two possibilities:

y = 8x^2 + 2x - 5 and y = 2x^2 + 8x - 5

To try to discard one of them, let us use the vertex, which is at x = -2.

With y = 8x^2 + 2x - 5, you get y = 8(-2)^2 + 2(-2) - 5 = 32 - 4 - 5 = 23 , which is not the y-coordinate of the vertex of the curve of the graph.

Test the other equation, y = 2x^2 + 8x - 5 = 2(-2)^2 + 8(-2) - 5 = 8 - 16 - 5 = -13, which is exactly the y-coordinate of the function graphed.

Then, the answer is 2x^2 + 8x  -5
8 0
3 years ago
CAN SOMEONE PLS HELP 6TH GRADE MATH ILL GIVE BRAINLIEST
ASHA 777 [7]

Answer:

14/100 and 7/50

Step-by-step explanation:

Basically you convert the decimal into a fraction, 14 percent is the same as 14/100 and if you simplify that then you get 7/50

4 0
3 years ago
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