Answer:
30 hens, 20 cows.
Step-by-step explanation:
Step one:
let the number of cows be x
and the number of hens be y
Each cow has 2 eyes, each hen has 2 eyes also.
the total number of eyes is
2x+2y
Each cow has 4 legs, each hen has 2 legs.
the total number of legs is
4x + 2y
Step two:
the number of legs exceeds the number of eyes by 40:
4x+2y - (2x+2y) = 40
open bracket
4x+2y-2x-2y=40
4x-2x=40
2x=40
Divide both sides by 2
x=40/2
x=20
Step three:
we know also that x = 2/3*y, so y = 3/2*x = 3/2 * 20 = 30
30 hens, 20 cows.
Check:
60 + 40 eyes = 100, 60 + 80 legs = 140legs.
<span>8y−5x=11
8y = 5x + 11
y = 5/8x + 11/8 has slope = 5/8
</span><span>a line that is perpendicular to the line, slope is opposite and reciprocal so slope = - 8/5
answer
slope = -8/5</span>
It would be x + y + 64
You subtract the -x from the 2x
(AB)^2 + (2 m)^2 = (8 m)^2, or
(AB)^2 + 4 m^2 = 64 m^2, or (AB)^2 = 60 m^2.
Taking the square root of both sides, (length of AB) = + 2sqrt(15) (answer)