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4 years ago

Given: angle Q is congruent to angle T and line QR is congruent to line TR

Mathematics

1 answer:

Ainat [17]4 years ago

3 0

3. Two angles and included side (ASA congruence theorem).

Reason: This is because, it is given that angle Q is congruent to angle T and line QR is congruent to line TR. Also, we proved in step 2 that $\angle PRQ\cong\angle SRT$ . Thus, we have two angles and the side included as congruent and thus, the two triangles are congruent.

4. CSCT (Corresponding Sides of a Congruent Triangle)

Reason: PR and SR are the corresponding sides of the congruent triangles $\Delta PRQ$ and $\Delta SRT$ , therefore, by the CSCT these corresponding sides have to be congruent.

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9. Solve x - 72 > 21.

castortr0y [4]

Inequalities are just like regular equations with only one exception. Which is when yo multiply or divide by a negative number to both sides of the inequality sign you must flip it. But, for this inequality that rule will no apply. So, what I do to make it easier because I know we all see a different sign in an equation and we start to freak out. So, change the inequality sign to an equals sign to get a hang of working with them.

Example of changing an inequality sign to an equals sign:

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Example of keeping the inequality sign

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3 years ago

How many years will it take for $2000 to double at a simple annual interest rate of 8%?

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3 years ago

Find the area with a height of 6.45 and base of 9.75

Kisachek [45]

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4 years ago

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una familia ha consumido en un dia de verano: dos botellas de litro y medio de agua, 5 botellas de 1/4 de litro de jjugo de appl

aleksandr82 [10.1K]

Answer:

La familia ha bebido en un día de verano $5\,\frac{1}{4}$ litros.

Step-by-step explanation:

Podemos evidenciar que es posible obtener el volumen total de los citados líquidos al sumar el volumen de cada uno. El volumen de cada bebida es igual al producto de su capacidad multiplicada por el número de botellas. Es decir:

$V_{total} = V_{agua} + V_{jugo} + V_{limonada}$

Donde todos los volúmenes se miden en litros.

$V_{total} = (2\,botellas)\times \left(\frac{3}{2} \,\frac{L}{botella} \right)+(5\,botellas)\times \left(\frac{1}{4}\,\frac{L}{botella} \right) + (4\,botellas)\times \left(\frac{1}{4}\,\frac{L}{botella} \right)$

$V_{total} = (2\,botellas)\times \left(\frac{6}{4} \,\frac{L}{botella} \right)+(5\,botellas)\times \left(\frac{1}{4}\,\frac{L}{botella} \right) + (4\,botellas)\times \left(\frac{1}{4}\,\frac{L}{botella} \right)$

$V_{total} = \frac{12}{4}\,L + \frac{5}{4} \,L + \frac{4}{4} \,L$

$V_{total} = \frac{21}{4}\,L$

$V_{total} = \frac{20}{4}\,L + \frac{1}{4}\,L$

$V_{total} = 5\,\frac{1}{4}\,L$

La familia ha bebido en un día de verano $5\,\frac{1}{4}$ litros.

3 0

3 years ago