Question

If h(x) = 3x − 1 and j(x) = −2x, solve h[j(2)] and select the correct answer below.

Answer 1

Answer:

Option 3rd is correct.

the value of h[j(2)]  is, -13

Step-by-step explanation:

Given the functions:

$h(x) = 3x-1$

$j(x) = -2x$

We have to find the value of  h[j(2)]

$h[j(x)] = h[-2x]$

Replace x from -2x in h(x) we have;

$h[-2x] = 3(-2x)-1 = -6x -1$

⇒$h[j(x)] = -6x-1$

Substitute the value of x = 2 we get;

$h[j(2)] = -6(2)-1 = -12-1 = -13$

Therefore, the value of h[j(2)]  is, -13

Answer 2

H(x) = 3x - 1
j(x) = -2x

h[j(2)] ⇒ j(2) = -2(2) ⇒ j(2) = -4

h(-4) = 3(-4) - 1
h(-4) = -12 - 1
h(-4) = -13

h[j(2)] = -13