Answer:
°
Step-by-step explanation:
"Theorem 9-13: The measure of an angle formed by two secants, two tangents, or a secant and a tangent drawn from a point outside the circle is equal to half the difference of the measures of the intercepted arcs."
Basically no matter what other circle, secant or tangent you get, you just use the formula
If you need the outer angle, just put the other angles in and solve
If you need the far or near point angle, re-arrange the formula to get that value.
All of the answers are correct except the last one
The polynomial p(x)=x^3-6x^2+32p(x)=x 3 −6x 2 +32p, left parenthesis, x, right parenthesis, equals, x, cubed, minus, 6, x, squar
Ray Of Light [21]
Answer:
(x-4)(x-4)(x+2)
Step-by-step explanation:
Given p(x) = x^3-6x^2+32 when it is divided by x - 4, the quotient gives
x^2-2x-8
Q(x) = P(x)/d(x)
x^3-6x^2+32/x- 4 = x^2-2x-8
Factorizing the quotient
x^2-2x-8
x^2-4x+2x-8
x(x-4)+2(x-4)
(x-4)(x+2)
Hence the polynomial as a product if linear terms is (x-4)(x-4)(x+2)
Since he drives 60 miles per hour we'll divide 272 by 60
272/60=4.5
it will take 4.5 hours
I hope I've helped!
Answer:
I think it's AB=BC.
Step-by-step explanation:
*I'm not in college, nor anywhere near college-level math, just a heads-up.*
Anyway, here's what I think. I turned my head around a bit to different angles, and I noticed the angle AB is the exact same length as BC, and both make the triangle a right angle. Try it if ya want, and see what happens. Sorry if this's wrong. I do hope it helps!