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Illusion [34]
3 years ago
10

Write an equation for the nth term of the given geometric sequence. 12, 156, 2028, ..., a

Mathematics
2 answers:
drek231 [11]3 years ago
7 0

Answer:  

12(13)^n-1 i took the test

Step-by-step explanation:

Katyanochek1 [597]3 years ago
5 0

Answer:

a(n) = 12 * (13)^(n-1)

Step-by-step explanation:

First step is to determine what's the scale/multiplication factor between each term:

156 / 12 = 13

2028 / 156 = 13

So, since we got 13 between 1st, 2nd and 3rd term, we can be confident it's the right multiplication factor.

an would be the first term (12) multiplied by a factor of 13. So,

an = 12 * (13)^{n-1}

If we try for n > 1, we have

a(2) = 12 * (13)^(2-1) = 12 * 13 = 156

a(3) = 12 * (13)^(3-1) = 12 * 13² = 12 * 169 = 2028

It matches!

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A train stops at Atlanta, then at Bayville, and then at Colleyville. The
Nezavi [6.7K]

Answer:

See Explanation

Step-by-step explanation:

<em>The question is incomplete as what is required of the question is not stated.</em>

<em>However, since the question is only limited to distance, a likely question could be to calculate the distance from Bayville to Colleyville.</em>

Represent the distance from Atlanta to Colleyville with AC

Represent the distance from Atlanta to Bayville with AB

Represent the distance from Bayville to Colleyville with BC

So, we have that:

AC = 25.5\ miles

AB = 10\frac{2}{3}\ miles

The relationship between AB, AC and BC is:

AC = AB + BC

Make BC the subject of formula:

BC = AC - AB

BC = 25.5 - 10\frac{2}{3}

Convert fraction to decimal

BC = 25.5 - 10.7

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<em>Hence, the distance from Bayville to Colleyville is 14.8 miles</em>

3 0
3 years ago
What is the image of ( 0 , -6 ) after a reflection over the line y = x?
Alla [95]

Answer:

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