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Illusion [34]
3 years ago
10

Write an equation for the nth term of the given geometric sequence. 12, 156, 2028, ..., a

Mathematics
2 answers:
drek231 [11]3 years ago
7 0

Answer:  

12(13)^n-1 i took the test

Step-by-step explanation:

Katyanochek1 [597]3 years ago
5 0

Answer:

a(n) = 12 * (13)^(n-1)

Step-by-step explanation:

First step is to determine what's the scale/multiplication factor between each term:

156 / 12 = 13

2028 / 156 = 13

So, since we got 13 between 1st, 2nd and 3rd term, we can be confident it's the right multiplication factor.

an would be the first term (12) multiplied by a factor of 13. So,

an = 12 * (13)^{n-1}

If we try for n > 1, we have

a(2) = 12 * (13)^(2-1) = 12 * 13 = 156

a(3) = 12 * (13)^(3-1) = 12 * 13² = 12 * 169 = 2028

It matches!

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ale4655 [162]

Answer: 0.000021 in scientific notation is

2.1 × 10-5

Step-by-step explanation:

All numbers in scientific notation or standard form are written in the form

m × 10n, where m is a number between 1 and 10 ( 1 ≤ |m| < 10 ) and the exponent n is a positive or negative integer.

To convert 0.000021 into scientific notation, follow these steps:

Move the decimal 5 times to right in the number so that the resulting number, m = 2.1, is greater than or equal to 1 but less than 10

Since we moved the decimal to the right the exponent n is negative

n = -5

Write in the scientific notation form m × 10n

= 2.1 × 10-5

Therefore,

2.1 × 10-5 is the scientific notation form of 0.000021 number and 2.1e-5 is the scientific e-notation form for 0.000021

** Hope this helps you! Good Luck!

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