Use the exponent properties to simplify the following
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1 answer:
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<h2><u>Problem Solving</u>:-</h2>
2. The table below shows that the distance d varies directly as the time t. Find the constant of variation and the equation which describes the relation.
<h2><u>Solution</u>:-</h2>Since the distance d varies directly as the time t, then d = kt.
Using one of the pairs of values, (2, 20), from the table, substitute the values of d and t in d = kt and solve for k.
- Therefore, the constant of variation is 10.
ANSWER:
The surface area of the star is 3.2700 x square kilometres.
EXPLANATIONS:
Diameter of the star = 1.8083 x Km.
Surface area of the star = 4
Where n is the radius of the star.
So that;
n =
= 0.90415 x
n = 0.90415 x Km
Thus,
Surface area = 4 x
= 326994889
Surface area = 3.2700 x
Therefore, the surface area of the star is 3.2700 x square kilometres.