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2 years ago

7

Use the exponent properties to simplify the following

z%5E3%7D" id="TexFormula1" title="\frac{3x^3y^2z}{27xy^2z^3}" alt="\frac{3x^3y^2z}{27xy^2z^3}" align="absmiddle" class="latex-formula">

1 answer:

7nadin3 [17]2 years ago

7 0

Step-by-step explanation:

x^2/9 z^2

hiiii checkout the steps

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Probability help please? In a certain instant lottery game, the chances of a win are stated as "1 in 19." Express the indicated

Vanyuwa [196]

The question is basically asking to find the chances in percentage. It is first given in fraction form, which is 1/19. This is approximately 0.053, once divided.

1/19 (One divided by 19)=0.0526

0.0526 rounded is about 0.053 (to three decimal places).

Answer: About 0.053

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3 years ago

I confused on this question.....how do you do it

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Which question, there is 5?

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2 years ago

A gym is selling monthly memberships for $35 each and reusable water bottles for $9 each. The gym

maks197457 [2]

Answer:

x = gym memberships, and y = bottles of water

30x + 7y = 1050.....when x = 28

30(28) + 7y = 1050

840 + 7y = 1050

7y = 1050 - 840

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y = 210/7

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Which of the following is a correct solution to the inequality 3x - 12 > 15?

pishuonlain [190]

Solve the inequality just like you would solve an equation
<span>3x - 12 > 15
add 12 to both sides
3x > 27
divide both sides by 3
x > 9
Or read as "the solution to </span><span>3x - 12 > 15 is x is greater than 9"

Hope this helps :)</span>

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2 years ago

a. A 2017 poll found that 56% of college students were very confident that their major will lead to a good job. If 15 college s

lesya [120]

Answer:

0.01083 or 1.083%

Step-by-step explanation:

This problem can be modeled as a binomial probability model with probability of success p = 0.56.

The probability of x=13 successes (a college student being very confident their major would lead to a good job) in a number of trials of n=15 is:

$P(X=x) = \frac{n!}{(n-x)!x!} *p^x*(1-p)^{n-x}\\P(X=13) = \frac{15!}{(15-13)!13!} *0.56^{13}*(1-0.56)^{15-13}\\P(X=13) = 0.01083=1.083\%$

The probability is 0.01083 or 1.083%.

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2 years ago