2. means that for every x, there is eactly one y
basically, we can use the vertical line test to see if it crosses at any 2 points
first one works
2nd one works
3rd works
4th works
5th works
they are all one to one functions
3.
easy
steps
for f(x)=?
replace f(x) with y
switch x and y
solve for y
replace y with f⁻¹(x)
so

replace

switch

solve

![\sqrt[3]{x+2}=1+y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B2%7D%3D1%2By)
![-1+\sqrt[3]{x+2}=](https://tex.z-dn.net/?f=-1%2B%5Csqrt%5B3%5D%7Bx%2B2%7D%3D)
replace
![f^{-1}(x)=-1+\sqrt[3]{x+2}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D-1%2B%5Csqrt%5B3%5D%7Bx%2B2%7D)
first option
4.
domain, hmm we can't divide by 0 so domain is all real numbers except for x=0
domain is

hmm, range
as x approaches negative or positive infinity, f(x)=5
as x approaches 0 from the left, f(x) appraoches negative infintiy
as x approaches 0 from the right , f(x) appraoches positive infintiy
so range is

domain is

range is

answer is the 4th option
AC = AC
answer
reflexive property
Answer:
the answer is 1.1 I think
Step-by-step explanation:
Answer: QS=68 units
Step-by-step explanation:
<em>RT=RS+ST</em>
<em>8x-43=2x-4+4x-1</em>
<em>8x-43=6x-5</em>
<em>8x-43-6x=6x-5-6x</em>
<em>2x-43=-5</em>
<em>2x-43+43=-5+43</em>
<em>2x=38</em>
<em>Divide both parts of the equation by 2:</em>
<em>x=19</em>
<em>QS=RS+RQ</em>
<em>As, RS=RQ</em>
<em>QS=2RS</em>
<em>QS=(2)((2)(19)-4))</em>
<em>QS=(2)(38-4)</em>
<em>QS=(2)(34)</em>
<em>QS=68</em>