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Blizzard [7]
3 years ago
7

The sum of the measures of three angles in a triangle is 180 degrees. The measure of one angle of a triangle is one degree more

than three times the measure of the smallest angle. The measure of the third angle is 13 degrees less than twice the measure of the second angle. Find the measure of each angle.(now the back of the book says the answers are 19 degree, 58 degree, & 103 degree)but I don't know how they got them.
Mathematics
1 answer:
sineoko [7]3 years ago
6 0

Answer:

19, 58 and 103

Step-by-step explanation:

Okay. Here we need to convert whatever statements we have into a mathematical expression.

Firstly, let’s give the smallest angle a value of x. Where do we now go from here? The measure of one angle is 1 degree greater than 3 times the size of the smallest angle. This means the value of the second angle is 3x + 1

Now for the third angle, the question stated that the third angle is thirteen degrees less than twice the measure of the second angle. The value for this is: 2( 3x + 1) - 13

Now when we add all these angles, surely, we get a result equal to 180.

x + 3x + 1 + 2(3x + 1) - 13 = 180

4x + 1 + 6x + 2 - 13 = 180

10x - 10 = 180

10x = 190 and x = 19.

Now the measure of the other angles are as follows:

3x + 1 = 3(19) + 1 = 57 + 1 = 58

2(3x + 1) - 13 = 2(58) - 13 = 103

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CALCULUS - Find the values of in the interval (0,2pi) where the tangent line to the graph of y = sinxcosx is
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Answer:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

Step-by-step explanation:

We want to find the values between the interval (0, 2π) where the tangent line to the graph of y=sin(x)cos(x) is horizontal.

Since the tangent line is horizontal, this means that our derivative at those points are 0.

So, first, let's find the derivative of our function.

y=\sin(x)\cos(x)

Take the derivative of both sides with respect to x:

\frac{d}{dx}[y]=\frac{d}{dx}[\sin(x)\cos(x)]

We need to use the product rule:

(uv)'=u'v+uv'

So, differentiate:

y'=\frac{d}{dx}[\sin(x)]\cos(x)+\sin(x)\frac{d}{dx}[\cos(x)]

Evaluate:

y'=(\cos(x))(\cos(x))+\sin(x)(-\sin(x))

Simplify:

y'=\cos^2(x)-\sin^2(x)

Since our tangent line is horizontal, the slope is 0. So, substitute 0 for y':

0=\cos^2(x)-\sin^2(x)

Now, let's solve for x. First, we can use the difference of two squares to obtain:

0=(\cos(x)-\sin(x))(\cos(x)+\sin(x))

Zero Product Property:

0=\cos(x)-\sin(x)\text{ or } 0=\cos(x)+\sin(x)

Solve for each case.

Case 1:

0=\cos(x)-\sin(x)

Add sin(x) to both sides:

\cos(x)=\sin(x)

To solve this, we can use the unit circle.

Recall at what points cosine equals sine.

This only happens twice: at π/4 (45°) and at 5π/4 (225°).

At both of these points, both cosine and sine equals √2/2 and -√2/2.

And between the intervals 0 and 2π, these are the only two times that happens.

Case II:

We have:

0=\cos(x)+\sin(x)

Subtract sine from both sides:

\cos(x)=-\sin(x)

Again, we can use the unit circle. Recall when cosine is the opposite of sine.

Like the previous one, this also happens at the 45°. However, this times, it happens at 3π/4 and 7π/4.

At 3π/4, cosine is -√2/2, and sine is √2/2. If we divide by a negative, we will see that cos(x)=-sin(x).

At 7π/4, cosine is √2/2, and sine is -√2/2, thus making our equation true.

Therefore, our solution set is:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

And we're done!

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So, if it costs $3.45 to purchase 3/4 lbs of chopped walnuts, it would cost $3.45 times 10 dollars to purchase 7.5 lbs of chopped walnuts, or $34.50.

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