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lapo4ka [179]
2 years ago
13

HELP PLS RIGHT NOWWW For Exercise 38, find each length. 38. AC

Mathematics
1 answer:
inessss [21]2 years ago
5 0

Answer:

Step-by-step explanation:

use the below to remember how to use trig functions ( copy this to your computer  for use later )

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

We can use TOA to find AC

Tan(31) = Opp / 9

9* Tan(31) = Opp   ( Opp = AC)

5.407745571 = AC

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Rampur Sarpanch requested one of his villager to donate a 6m wide land adjusted to his 132.8m long side of his right triangular
Furkat [3]

Answer:

The answer is 3030.72 m³

Step-by-step explanation:

Please refer to attached file for graphical representation.

Formulas used:

Area = (a*b)/2

Trigonometry: Tan (t) = opposite/adjacent

Assume:

Villager plot has 3 sides: hypotenuse=C, adjacent=A, opposite=B

Plot given has 3 sides: hypotenuse=z, adjacent=y, opposite=x

Angle common between them is t.

<u>Step 1</u>:

For t:

Tan (t) = a/b

Tan (t) = 123/50

Tan (t) = 2.46

<u>Step 2:</u>

For y:

Tan (t) = y/x

2.46 = y/6

y = 2.46*6

y = 14.76

<u>Step 3:</u>

Villagers old plot area: B = (a*b)/2 = (123*50)/2

B = 3075 m³

<u>Step 4:</u>

Plot donated area: C = (x*y)/2 = (6*14.76)/2

C = 44.28 m³

<u>Step 5:</u>

Villager remaining plot:

A = B-C

A= 3075-44.28

A = 3030.72 m³

Download docx
7 0
3 years ago
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