Step-by-step explanation:
Draw diagonal AC
The triangle ABC has sides 17 and 25
Say AB is 17, BC is 25
Draw altitude on side BC from A , say h
h = 17 sin B
Area = 25*17 sin B = 408
sin B = 24/25
In ∆ ABC
Cos B = +- 7/25
= 625 + 289 — b^2 / 2*25*17
b^2 = 914 — 14*17 = 676
b = 26
h = 17*24/25 = 408/25 = 16.32
Draw the second diagonal BD
In ∆ BCD, draw altitude from D, say DE =h
BD^2 = h^2 + {(25 + sqrt (289 -h^2) }^2
BD^2 = 16.32^2 + (25 + 4.76)^2
= 885.6576 + 266.3424
BD = √ 1152 = 33.94 m
Answer:
y = 3x - 7
Step-by-step explanation:
The <em>point-slope formula</em> for a straight line is
y – y₁ = m(x – x₁)
x₁ = 4; y₁ = 5; m = 3 Substitute the values
y – 5 = 3(x - 4) Remove parentheses
y – 5 = 3x - 12 Add 5 to each side
y = 3x - 7
The graph is a straight line with a y-intercept at y = -7 and a slope = 12/4 = 3.
Answer:
it helps sharpen ur brain up for future so as not to be cheated by others
1 = 51
2= 61
3= 29
Step-by-step explanation:
1) 61+68= 129
180-129= 51
2) 61 is across it so they have the same number
3) 61 +90= 151
180-151= 29
Answer:
yes the sides of a triangle can have all those sides
