QUESTION:- EVALUATE THE EXPRESSION
EXPRESSION:-
![{( \sqrt[6]{27 {a}^{3} {b}^{4} } )}^{2}](https://tex.z-dn.net/?f=%7B%28%20%5Csqrt%5B6%5D%7B27%20%7Ba%7D%5E%7B3%7D%20%20%7Bb%7D%5E%7B4%7D%20%7D%20%29%7D%5E%7B2%7D%20)
<h3>ANSWER-></h3>
![\\ ANSWER->3ab \sqrt[3]{b} \: \: \: \: \: or \: \: 3a {b}^{ \frac{4}{3} }](https://tex.z-dn.net/?f=%20%5C%5C%20ANSWER-%3E3ab%20%5Csqrt%5B3%5D%7Bb%7D%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20or%20%5C%3A%20%5C%3A%203a%20%7Bb%7D%5E%7B%20%5Cfrac%7B4%7D%7B3%7D%20%7D%20)
Answer:
D
Step-by-step explanation:
The question says 6 is greater than x. That means that 5 is the highest it can go and it can not get any higher so you have to go backwards.
Answer:
<em>summation of five times negative three to the power of n from n equals zero to infinity</em>
Step-by-step explanation:
<u>Summation Notation
</u>
It represents the sum of a finite or infinite number of terms. Let's analyze the terms of the given succession:
5-15+45-135+...
If we take 5 as a common factor, we have
5(1-3+9-27+...)
The parentheses contain the alternate sum/subtraction of powers of 3. The odd terms are positive, the even terms are negative, thus the exponent must be n starting from 0 or n-1 starting from 1
The summation is then represented by

This corresponds with the option:
<u>summation of five times negative three to the power of n from n equals zero to infinity</u>
Answer:
Step-by-step explanation:
2x+5y=12
3x+4y=11
---------------
3(2x+5y)=3(12)
-2(3x+4y)=-2(11)
-----------------------
6x+15y=36
-6x-8y=-22
-----------------
7y=14
y=14/7=2
2x+5(2)=12
2x+10=12
2x=12-10=2
x=2/2=1
x=1, y=2. (1, 2)
---------------------
I just provided you an example of a system of equations and I already solved it for you.
<em>Hey mate!!!!! yes we can see the picture but what do you want us to do for you??</em>