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3 years ago

5

B is the midpoint of AC. If AB =x +5 and BC = 2x -11, find the measure of AB

1 answer:

bogdanovich [222]3 years ago

8 0

If B is the midpoint of AC, that means the the line segments connecting the endpoints to the midpoints are the same length, or: AB = BC. With that in mind, we can set their lengths equal to each other:

x + 5 = 2x - 11

From there, simply solve for x and input that result back into the expression for AB (x + 5) and you’ll have your result.

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<h3>Answer: 4 units</h3>

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Work Shown:

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3 years ago

The diameter of a quarter is 24.26 mm and the diameter of a nickel is 21.21 mm. How much bigger is the distance around a quarter

olga55 [171]

Answer:

9.577 mm.

Step-by-step explanation:

We have been given that the diameter of a quarter is 24.26 mm and the diameter of a nickel is 21.21 mm.

Let us find the circumference of quarter and nickel using circumference of circle formula.

$\text{Circumference of circle}=2\pi r$ , where r represents radius of the circle.

Since we know that diameter of circle is 2 times its radius, so let us find radius of quarter and nickel by dividing their diameter by 2.

$\text{Radius of quarter}=\frac{24.26}{2}$

$\text{Radius of quarter}=12.13$

$\text{Radius of nickel}=\frac{21.21}{2}$

$\text{Radius of nickel}=10.605$

$\text{Circumference of quarter}=2\times 3.14\times 12.13$

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Therefore, circumference of quarter is 76.1764 mm.

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$\text{Circumference of nickel}=2\times 3.14\times 10.605$

$\text{Circumference of nickel}=66.5994$

Let us subtract circumference of nickel from circumference of quarter.

$\text{The difference between distance around quarter and nickel}=76.1764-66.5994$

$\text{The difference between distance around quarter and nickel}=9.577$

Therefore, the distance around a quarter is 9.577 millimeters bigger than a nickel.

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