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Scorpion4ik [409]
3 years ago
7

B) 192.75

Mathematics
2 answers:
OleMash [197]3 years ago
6 0
B) 192.75
Place Value Chart with Decimals

ten thousand: 0
thousands:0
hundreds:1
tens: 9
ones: 2
tenths: 7
hundredths:5
thousandths:0

Expanded Notation: 100+90+02+.70+.05

Word Form: One hundred, Ninety Two (point or and) seventy five tenths
dangina [55]3 years ago
4 0

Answer:

192.75 is 1 one hundred - 9 tens - 2 ones - 7 tenths and 5 hundredths. if that's the answer you need

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In a basketball game, Team A defeated Team B with a score of 97 to 63. Team A won by scoring a combination of two-point baskets,
-BARSIC- [3]

Answer:

14 free throw baskets , 25 two point baskets and 11 three point baskets

Step-by-step explanation:

Let n₁ represent the number of free-throw baskets, n₂ represent the number of two point baskets and n₃ represent the number of three point baskets.

Now, from the question, the number of two point baskets, n₂ is greater than the free throw baskets by 11. This is written as n₂ = n₁ + 11. Also, the number of three point baskets n₃ is three less than the number of free point baskets. This is written as n₃ = n₂ - 3. Since our total number of points equals 97, it follows that, sum of number of points multiplied by each point equals 97. So, ∑(number of points × each point) = 97. Thus,

n₁ + 2n₂ + 3n₃ = 97. Substituting n₂ and n₃ from above, we have n₁ +2(n₁ + 11) + 3(n₁ - 3) = 97.

Expanding the brackets, we have, n₁ + 2n₁ + 22 + 3n₁ - 9 = 97

collecting like terms, we have 6n₁ + 13 = 97

6n₁ = 97 - 13

6n₁ = 84

dividing through by n₁ we have, n₁ = 84/6 =14

so n₁ our free throw baskets equals 14. Substituting this into n₂ our number of two point baskets equals n₂ = n₁ + 11 = 14 + 11 = 25. Our number of three point baskets n₃ = n₁ - 3. So, n₃ = 14 -3 = 11.

7 0
3 years ago
Read 2 more answers
Please help! If the current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms, what is the voltage?
Leona [35]

The value of the voltage is 18 - j volts if the current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms option (c) is correct.

<h3>What is a complex number?</h3>

It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.

We have:

The current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms.

As we know,

V = IR

V = (3 + j2)(4 - j3)

\rm V=\left(3\cdot \:4-2\left(-3\right)\right)+\left(3\left(-3\right)+2\cdot \:4\right)j

j² = -1 (complex part)

After simplification:

V = 18 - j  volts

Thus, the value of the voltage is 18 - j volts if the current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms option (c) is correct.

Learn more about the complex number here:

brainly.com/question/10251853

#SPJ1

6 0
2 years ago
Whats the answer for this problem ?
riadik2000 [5.3K]
The answer is Square *8=h
I hope this helps.
6 0
3 years ago
Read 2 more answers
(5^3)^1<br> Find the value, and Write the answer without exponents
beks73 [17]

Answer:

125

Step-by-step explanation:

u do 5 to the power of 3 then to the power of 1. yw.

7 0
3 years ago
What is the multiplicative inverse of 1 2/3 divide by 12
Gemiola [76]
"<span>What is the multiplicative inverse of 1 2/3 divide by 12?"

Suppose you actually divide 1 2/3 by 12:   (5/3) / 12 = (5/36).
Now, if you multiply this (5/36) by 12, you'll get (5/3), which is the same as
1 2/3.</span>
6 0
3 years ago
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