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Radda [10]
2 years ago
10

Please help! If the current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms, what is the voltage?

Mathematics
1 answer:
Leona [35]2 years ago
6 0

The value of the voltage is 18 - j volts if the current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms option (c) is correct.

<h3>What is a complex number?</h3>

It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.

We have:

The current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms.

As we know,

V = IR

V = (3 + j2)(4 - j3)

\rm V=\left(3\cdot \:4-2\left(-3\right)\right)+\left(3\left(-3\right)+2\cdot \:4\right)j

j² = -1 (complex part)

After simplification:

V = 18 - j  volts

Thus, the value of the voltage is 18 - j volts if the current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms option (c) is correct.

Learn more about the complex number here:

brainly.com/question/10251853

#SPJ1

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<u>First, add by 1/8 from both sides.</u>

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I hope this helps you! Let me know if my answer is wrong or not.

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