3 years ago

Find domain of gg(x)=x+5/2x^2-x-3

1 answer:

3 0

$g(x)=\frac{x+5}{2x^2-x-3}\\\\D_g:\\2x^2-x-3\neq0\\\\2x^2+2x-3x-3\neq0\\\\2x(x+1)-3(x+1)\neq0\\\\(x+1)(2x-3)\neq0\iff x+1\neq0\ \wedge\ 2x-3\neq0\\\\x\neq-1\ \wedge\ x\neq1.5\\\\D_g:x\in\mathbb{R}\ \backslash\ \{-1;\ 1.5\}$

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