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3 years ago

Find domain of gg(x)=x+5/2x^2-x-3

1 answer:

3 0

$g(x)=\frac{x+5}{2x^2-x-3}\\\\D_g:\\2x^2-x-3\neq0\\\\2x^2+2x-3x-3\neq0\\\\2x(x+1)-3(x+1)\neq0\\\\(x+1)(2x-3)\neq0\iff x+1\neq0\ \wedge\ 2x-3\neq0\\\\x\neq-1\ \wedge\ x\neq1.5\\\\D_g:x\in\mathbb{R}\ \backslash\ \{-1;\ 1.5\}$

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Ludmilka [50]

Answer:

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Step-by-step explanation:

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Since there are three sides it can be safely assumed that storage unit is rectangular in shape.

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Using the above formula in the given dimension we have

volume of storage unit = length of storage unit * width of storage unit * height of storage unit

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3 years ago

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elena-s [515]

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3 years ago

Read 2 more answers

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nordsb [41]

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3 years ago

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MatroZZZ [7]

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3 years ago

If x=-7 is a root of the equation x^2+kx+49=0, then k=

aleksley [76]

Answer:

$k=14$

Step-by-step explanation:

Given:

$x^{2}+kx+49 = 0$

$x = -7$

Substitution can be used to find the value of $k$ :

$(-7)^{2}+(-7)k+49 = 0$

$49-7k+49 = 0$

$98 -7k = 0$

$k = 14$

Hope this helps :)

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3 years ago