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Gala2k [10]
3 years ago
5

1. Find the value of 8.3 x 24.2 x 0.03. Round your answer to the nearest hundredth.

Mathematics
1 answer:
MrMuchimi3 years ago
5 0

The rounded value is option B) 6.03 which is rounded to the nearest hundredth.

<u>Step-by-step explanation:</u>

  • To find the value of 8.3 x 24.2 x 0.03, we need to multiply the given numbers to get a decimal value.
  • And then, after getting the value of 8.3 x 24.2 x 0.03 it should be rounded to the nearest hundredth.

<u>So, let's multiply the numbers first :</u>

8.3 × 24.2 × 0.03 = 6.0258

The value is 6.0258

<u>To round the value 6.0258 to the nearest hundredth :</u>

  • The first number next to the decimal point represents the tenth.
  • The second number next to the decimal point is the hundredth.
  • The third number next to the decimal point is thousandth.

Therefore, to round the value to the nearest hundredth, look for the thousandth number is either less than 5 or greater and or equal to 5.

If, thousandth place is greater or equal to 5, then the hundredth number should be increased by 1.

The hundredth is 6.02 and the number in the thousandth place is 5. So add 1 to the hundredth place.

The value is rounded to 6.03 to the nearest hundredth.

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Answer:

The required formula is:

                                                          {\displaystyle \ a_{n}=a_{1}+(n-1)d}

Step-by-step explanation:

The total number of squares of the the first term = 4

The total number of squares of the the second term = 7

The total number of squares of the the third term = 10

so,

a_1=4

a_2=7

a_3=10

Finding the common difference d

d=a_3-a_2=10-7=3

d=a_2-a_1=7-4=3

As the common difference 'd' is same, it means the sequence is in arithmetic.

So

If the initial term of an arithmetic progression is {\displaystyle a_{1}} and the common difference of successive members is d, then the nth term of the sequence (a_n) is given by:

                         {\displaystyle \ a_{n}=a_{1}+(n-1)d}

Therefore, the required formula is:

                                                          {\displaystyle \ a_{n}=a_{1}+(n-1)d}

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